The magnetic field around the head has been measured to be approximately 2.0×10−8 gauss . Although...

The magnetic field around the head has been measured to be approximately 2.0×10−8 gauss . Although the currents that cause this field are quite complicated, we can get a rough estimate of their size by modeling them as a single circular current loop 14 cm (the width of a typical head) in diameter.

What is the current needed to produce such a field at the center of the loop?

Expert Solution

According to the given problem,

Using the Given data,

Magnetic field around the head, B = 2.0 * 10^-8 G

= (2.0 * 10^-8 G) (10^-4 T / 1 G)

= 2.0 * 10^-12 T

Diameter of the current loop, d = 14 cm

Radius of the current loop, R = 7 cm

= 0.07 m

Now, the magnitude of the magnetic field at the center of a circular

loop carrying current I is given by

B = μ₀ I / 2 R

2.0 * 10^-12 T = (4 π * 10^-7 T.m/A) I / 2(0.07 m)

I = 2.23 *10^-7 A.

I hope you understood the problem, If yes rate me!! or else comment for a better solution.

genius_generous answered 2 years ago

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