Question

In: Statistics and Probability

It has been suggusted that the highest priority of retirees is travel. Thus, a study was...

It has been suggusted that the highest priority of retirees is travel. Thus, a study was conducted to investigate the differences in the length of stay of a trip for pre- and post-retirees. A sample of 691 travelers were asked how long they stayed on a typical trip. The observed results of the study are found below.

Number of Nights Pre-retirement Post-retirement Total
4−7 235 175 410
8−13 84 63 147
14−21 31 59 90
22 or more 12 32 44
Total 362 329 691


With this information, construct a table of estimated expected values.

Number of Nights Pre-retirement Post-retirement
4−7
8−13
14−21
22 or more


Now, with that information, determine whether the length of stay is independent of retirement using α=0.01.

(a)  χ2=

(b) Find the degrees of freedom:

(c) Find the critical value:  

Solutions

Expert Solution

We have to find out Expected Frequencies:

Ei = (Corresponding row total * Corresponding column total) / sample size

For First cell:

E1 = (410 * 362) / 691 = 214.79

E2 = (410 * 329) / 691 = 195.21

Similarly solve for all other cells,

We have calculated for expected frequencies and presented in the following table:

Expected Frequencies:

Number of Nights Pre -retirement Post-retirement Total
4 - 7 214.79 195.21 410.00
8 - 13 77.01 69.99 147.00
14 - 21 47.15 42.85 90.00
22 or more 23.05 20.95 44.00
Total 362.00 329.00 691.00

a)

Computational Table:

Oi Ei (Oi-EI) (Oi-Ei)2 (Oi-Ei)2/Ei   
235 214.79 20.21 408.4377 1.901566
84 77.01 6.99 48.85828 0.63444
31 47.15 -16.15 260.7921 5.531226
12 23.05 -11.05 122.1169 5.297763
175 195.21 -20.21 408.4377 2.092301
63 69.99 -6.99 48.85828 0.698076
59 42.85 16.15 260.7921 6.08603
32 20.95 11.05 122.1169 5.82915
Total 691 691.00 28.07

Test statistic:

b)

Degrees of Freedom = (r-1) * (c-1)

Where, r = Number of rows = 4

c = Number of columns = 2

Degrees of Freedom = (r-1) * (c-1) = (4-1) * (2-1) = 3*1 = 3

C)

Critical value:

.........................From Chi square table

Conclusion:

Test statistic > Critical value, i.e. 28.07 > 11.34, That is Reject Ho at 1% level of significance.

Therefore, The length of stay is dependent of retirement


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