What is the hydroxide-ion concentration in a 0.22 M solution of Na2CO3? For carbonic acid, Ka1...

What is the hydroxide-ion concentration in a 0.22 M solution of Na2CO3? For carbonic acid, Ka1 = 4.2  10–7 and Ka2 = 4.8  10–11

Expert Solution

CO3^2- + H2O --------> HCO3^- + OH^-

I 0.22 0 0

C -x +x +x

E 0.22-x +x +x

Kb = Kw/Ka2

= 1*10^-14/4.8*10^-11

= 2.1*10^-4

Kb = [HCO3^-][OH-]/[CO3^2-]

2.1*10^-4 = x*x/0.22-x

2.1*10^-4 *(0.22-x) = x²

x = 0.0067

[OH-] = x = 0.0067M

queen_honey_blossom answered 1 year ago

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