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In: Chemistry

A hypothetical element consists of two isotopes of masses 70.95 amu and 72.95 amu with abundances...

A hypothetical element consists of two isotopes of masses 70.95 amu and 72.95 amu with abundances of 30.9% and 69.1%, respectively. What is the average atomic mass of this element?

Solutions

Expert Solution

isotopes of masses : m1= 70.95 amu

                                 m2 = 72.95 amu

abundances :       A1 = 30.9 % = 0.309

                             A2 = 69.1% = 0.691

average atomic mass = ( atomic mass of isotope 1 x abundance 1 + atomic mass of isotope 2 x abundance 2 )

                                    = (70.95 x 0.309 + 72.95 x 0.691)

                                    = 72.33 amu

average atomic mass    = 72.33 amu


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