In: Economics
Given the following independent projects, all of which can be considered to be viable for only 10 years. If the company's MARR is 15% per year, determine which should be selected on the basis of a present worth analysis. Financial Values are in $1,000 units.
Projects | A | B | C | D |
First Cost, $ | -1200 | -2000 | -5000 | -7000 |
Annual net Income, $/Year | 300 | 400 | 1100 | 1300 |
Salvage Value | 5 | 6 | 8 | 9 |
Group of answer choices
A.) B and C
B.) A, B, and C
C.) A and C
D.) A and B
MARR = 15%
Life of Alternatives = 10 years
All the values are in 1,000 units
Projet A
Initial Cost = -1200
Annual Income = 300 per year
Salvage Value = 5
PW = -1,200 + 300 (P/A, 15%, 10) + 5 (P/F, 15%, 10)
PW = -1,200 + 300 (5.018768) + 5 (0.247184) = 306.86
Projet B
Initial Cost = -2000
Annual Income = 400 per year
Salvage Value = 6
PW = -200 + 400 (P/A, 15%, 10) + 6 (P/F, 15%, 10)
PW = -2,000 + 400 (5.018768) + 6 (0.247184) = 8.99
Projet C
Initial Cost = -5000
Annual Income = 1100 per year
Salvage Value = 8
PW = -5000 + 1100 (P/A, 15%, 10) + 8 (P/F, 15%, 10)
PW = -5000 + 1100 (5.018768) + 8 (0.247184) = 522.62
Projet D
Initial Cost = -7000
Annual Income = 1300 per year
Salvage Value = 9
PW = -7000 + 1300 (P/A, 15%, 10) + 9 (P/F, 15%, 10)
PW = -7,000 + 1300 (5.018768) + 9 (0.247184) = -473.37
Answer - B) A, B and C
The alternative A, B and C can se selected as the PW is positive. The alternative D is having a negative PW, so it is to be rejected.