In: Nursing
Question 1
The character of the genetic defect in Huntington’s disease explains many feature and nature of inheritance too. The responsible gene is located at 4p16 position and the prior cause of the disease is alteration/increase in the repetition of nucleic acid C, A and G in coding region. This CAG “triplet” is in normal condition will be repeated around 20 times whereas the expression of the disease occurs when this repetition exceeds 40 or more. In this particular case as the father exhibits a CAG repeats of 37 that symbolize the expression of the HD gene (genotype) in P generation although the reduced penetrance does not allow exhibiting the disease in father whereas F1 generation inherited the disease in their major phenotypic traits. Many research reports also suggested that the descendents of the persons in the range of 26-38 used to transmit the HD as a phenotypic trait as their genotypic expression for the HD gene is much higher than normal range.
Question 2
HD is a dominantly inherited desease. Hence, if this patient has a child with an unaffected female, the child will have a 50% chance of developing HD.
All are having two copies of each gene. Consider the father has HD and the mother doesn’t have that means mother has two good copies of the gene whereas father has one broken copy of the gene and one good copy. Hence, the child will get one of them randomly, thereby chances of getting the broken faulty copy are one in two or 50%.