In: Biology
Since the parent is affected and heterozygous, therefore the disease Huntington's disease must be dominant. Let the disease be represented by H. Thus, only H or HH can be diseased. If another parent be unaffected,the genotype has to be hh ( recessive,must be in pairs)
Thus,
Parents Hh x hh
Gametes H h h h
Offsprings Hh Hh hh hh
50% will be diseased and 50% unaffected.
Cystic Fibrosis,
2 parents who are heterozygous carriers. Since Cystic Fibrosis isa recessive disease, it will be expresed only when both are cc.
Let the normal be CC or Cc
2 parents are heterozygous carriers
Parents Cc x Cc
Gametes C c x C c
Offsprings CC Cc Cc cc
The first 3 offsprings wont get the disease. CC will be normal
Cc will be carriers.
cc will be affected.
a. 1 out of 4 i.e. 25% will be having the disease cystic Fibrosis.
b. 2 out of 4 will be carriers. Cc, 50% carriers.
c. 1 out of 4 will be a homozygous normal, 25%. CC.