Question

In: Statistics and Probability

To begin answering our original question, test the claim that the proportion of children from the...

To begin answering our original question, test the claim that the proportion of children from the low income group that drew the nickel too large is greater than the proportion of the high income group that drew the nickel too large. Test at the 0.1 significance level.

Recall 19 of 40 children in the low income group drew the nickel too large, and 7 of 35 did in the high income group.

a) If we use LL to denote the low income group and HH to denote the high income group, identify the correct alternative hypothesis.

  • H1:μL>μH
  • H1:pL>pH
  • H1:pL≠pH
  • H1:μL≠μH
  • H1:pL<pH
  • H1:μL<μH

b) The test statistic value is:

c) Using the P-value method, the P-value is:

d) Based on this, we

  • Reject H0H0
  • Fail to reject H0

e) Which means

  • There is not sufficient evidence to warrant rejection of the claim
  • The sample data supports the claim
  • There is not sufficient evidence to support the claim
  • There is sufficient evidence to warrant rejection of the claim

Solutions

Expert Solution

Answer :

Given data is :

Significance level

Here

= 19 / 40 = 0.475

= 7 / 35

= 0.2

therefore,

= (19 + 7) / (40 + 35)

= 26 / 75

= 0.347

then q = 1 - p = 1 - 0.347 = 0.653

Based on these,

a)

Null hypothesis is :

Alternative hypothesis is :

b)

Test statistics Z =

=

=

=

=

=

=

Test statistics Z = 2.49

c)

From z table values,

P value = 1 - P(Z <= 2.49)

= 1 - 0.9936

= 0.0064

P value = 0.0064

d)

We get P value < 0.10

So,we reject null hypothesis.

i.e Reject

e)

The sample data supports the claim


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