In: Statistics and Probability
To begin answering our original question, test the claim that
the proportion of children from the low income group that drew the
nickel too large is greater than the proportion of the high income
group that drew the nickel too large. Test at the
0.1 significance level.
Recall 19 of 40 children in the low income group drew the nickel
too large, and 7 of 35 did in the high income group.
a) If we use LL to denote the low income group and HH to denote the
high income group, identify the correct alternative
hypothesis.
b) The test statistic value is:
c) Using the P-value method, the P-value is:
d) Based on this, we
e) Which means
Answer :
Given data is :
Significance level
Here
= 19 / 40 = 0.475
= 7 / 35
= 0.2
therefore,
= (19 + 7) / (40 + 35)
= 26 / 75
= 0.347
then q = 1 - p = 1 - 0.347 = 0.653
Based on these,
a)
Null hypothesis is :
Alternative hypothesis is :
b)
Test statistics Z =
=
=
=
=
=
=
Test statistics Z = 2.49
c)
From z table values,
P value = 1 - P(Z <= 2.49)
= 1 - 0.9936
= 0.0064
P value = 0.0064
d)
We get P value < 0.10
So,we reject null hypothesis.
i.e Reject
e)
The sample data supports the claim