In: Statistics and Probability
Determine the standardized test Zo, to test the claim about the population proportion p not equal to o.325 given n = 42 and phat=.247. Use significance sign = 0.05
null Hypothesis: Ho: p | = | 0.325 | |
alternate Hypothesis: Ha: p | ≠ | 0.325 |
for 0.05 level with two tailed test , critical z= | 1.9600 | ||
Decision rule : reject Ho if absolute value of test statistic |z|>1.96 |
sample size n = | 42 | |
std error se =√(p*(1-p)/n) = | 0.0723 | |
sample proportion p̂ = x/n= | 0.2470 | |
test stat z0 =(p̂-p)/√(p(1-p)/n)= | -1.08 |
since test statistic does not falls in rejection region we fail to reject null hypothesis |