In: Biology
If the a and b loci are 20 cM apart and an AA BB individual and an aa bb individual mate: What gametes will the F1 individuals produce, and in what proportions? What phenotypic classes in what proportions are expected in the F2 generation (assuming complete dominance for both genes) (show procedure)
As a & b loci are 20 cM apart, 20% recombination can occur between them.
Parental cross AA BB x aa bb
Parental gametes AB (From AA BB) & ab (From aa bb)
F1 genotype AB/ab
Now, as 20% recombination occur between a & b loci, 80% gametes in F1 will be parental (Non-recombinant) & 20% gametes will be recombinants.
So, we will get AB & ab each of 40% frequency or 0.4; Ab & aB each of 10% frequency or 0.1.
F1 gametes AB (0.4), ab (0.4), Ab (0.1) & aB (0.1)
Now, two F1 will be crossed to produce F2. The cross between them is shown in below Punnett square.
Gamete (Frequency) | AB (0.4) | Ab (0.1) | aB (0.1) | ab (0.4) |
---|---|---|---|---|
AB (0.4) | AA BB (0.16) | AA Bb (0.04) | Aa BB (0.04) | Aa Bb (0.16) |
Ab (0.1) | AA Bb (0.04) | AA bb (0.01) | Aa Bb (0.01) | Aa bb (0.04) |
aB (0.1) | Aa BB (0.04) | Aa Bb (0.01) | aa BB (0.01) | aa Bb (0.04) |
ab (0.4) | Aa Bb (0.16) | Aa bb (0.04) | aa Bb (0.04) | aa bb (0.16) |
From the above Punnett square, we find that in F2 we will observe A_B_: A_bb: aaB_: aabb in 0.66:0.09:0.09:0.16 or 66:9:9:16 ratio.