In: Chemistry
If ?H = -60.0kJ and ?S = -0.300kJ/K , the reaction is spontaneous below a certain temperature. Calculate that temperature.
We know that
G =
H-T
S
Where
G = change in
Gibb's free energy
H = change in
enthalpy = - 60.0 KJ
S = change in
entropy = -0.300 KJ/K
T = temperature in K
The reaction is spontaneous iff
G < 0
H-T
S
< 0
H < T
S
T >
H /
S
T > -60 KJ / -0.300 KJ/K
T > 200 K
The temperature is 200 K