In: Chemistry
Determine the binding energy (in MeV) per nucleon for the nuclides: a) 816O, b) 817O, c) 2656Fe, d) 92235U
please show steps!
Answer – a) 168O
We know exact mass of O = 15.9949 amu
In the 168O there are 8 protons and , 16-8 = 8 neutrons
Mass of neutron =1.008665 amu
mass of proton = 1.007825 amu
So mass of 168O = (8*1.007825) + (8*1.008665)
= 16.1319 amu
So mass defec, Δm = 16.1319 amu - 15.9949 amu
= 0.1370 amu
We know,
Energy = Δm *931.494 MeV/amu
= 0.1370 amu* 931.494 MeV/amu
= 127.63 MeV
Binding energy in MeV per nucleons =127.63 MeV /16 nucleons
= 7.98 MeV/nucleons
b) 178O
mass of 178O = (8*1.007825) + (9*1.008665)
= 17.1406 amu
So mass defec, Δm = 17.1406 amu – 16.9991 amu
= 0.1415 amu
We know,
Energy = Δm *931.494 MeV/amu
= 0.1415 amu* 931.494 MeV/amu
= 131.8 MeV
Binding energy in MeV per nucleons =131.8 MeV /17 nucleons
= 7.75 MeV/nucleons
c) 5626Fe
mass of 5626Fe = (26*1.007825) + (30*1.008665)
= 56.4634 amu
So mass defec, Δm = 56.4634 amu – 55.9349 amu
= 0.5285 amu
We know,
Energy = Δm *931.494 MeV/amu
= 0.5285 amu* 931.494 MeV/amu
= 492.29 MeV
Binding energy in MeV per nucleons =492.29 MeV /56 nucleons
= 8.79 MeV/nucleons
d) 23592U
mass of 23592U = (92*1.007825) + (143*1.008665)
= 236.9589 amu
So mass defec, Δm = 236.9589 amu – 235.0439 amu
= 1.91 amu
We know,
Energy = Δm *931.494 MeV/amu
= 1.91amu* 931.494 MeV/amu
= 1783.9 MeV
Binding energy in MeV per nucleons =17839 MeV /235 nucleons
= 7.59 MeV/nucleons