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Calculate the total binding energy and the binding energy per nucleon of (a) 7 Be, (b)...

Calculate the total binding energy and the binding energy per nucleon of (a) 7 Be, (b) 56 Fe

Solutions

Expert Solution

(b)Iron

Mass number=56

No of protons= 26

no of neutrons= 30

mass of Iron nucleus = 55.9349375u ( atomic mass unit)

mass of each proton =1.007276u

mass of neutron =1.008664u

mass of totoal number of protons =26.189176u

mass of total number of neutrons=30.25992u

total mass of nucleons =56.449096u

mass defect= 56.449096-55.9349375= 0.5141585u

binding energy =

c= m/s

1u= 931.494Mev/

binding energy = 478.93555Mev

binding energy per nucleon =  478.93555Mev/56= 8.55Mev

(a) Be

Mass number=7

No of protons= 4

no of neutrons= 3

mass of Iron nucleus = 7.0169u ( atomic mass unit)

mass of each proton =1.007276u

mass of neutron =1.008664u

mass of total number of protons (4) =4.029104u

mass of total number of neutrons (3)=3.025992u

total mass of nucleons =7.055096u

mass defect= 0.038176u

binding energy =

c= m/s

1u= 931.494Mev/

binding energy = 35.5607Mev

binding energy per nucleon = 35.5607Mev/7= 5.08Mev

genius_generous answered 2 years ago
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