In: Finance
A certain piece ofequipment has an initial cost of $10,000 with an annual maintenance cost of $500 per year with no salvage value at the end of its useful life of 4 years. There is an alternative equipment that costs $20,000 with no maintenance cost the first year. However, it has a maintenance cost of $100 the second year and increases $100 per year in subsequent years. Its salvage value is $5,000 and has a useful life of 12 years. The MARR is 8%. Which machine should be selected?
Machine A | Machine B | |||||||||||||||
Step : 1 | Initial Investment | -10,000 | -20,000 | |||||||||||||
Step : 2 | Salvage | NIL | ||||||||||||||
Step : 3 | Cash Flow | |||||||||||||||
Particulars | Year (1 to 4) | Year 1 | Year 2 | Year 3 | Year 4 | Year 5 | Year 6 | Year 7 | Year 8 | Year 9 | Year 10 | Year 11 | Year 12 | Total | ||
Annual Maintainance Cost | -500 | - | -100 | -200 | -300 | -400 | -500 | -600 | -700 | -800 | -900 | -1,000 | -1,100 | |||
5,000 | ||||||||||||||||
Discounting Factor | 3.3121 | 0.9259 | 0.8573 | 0.7938 | 0.7350 | 0.6806 | 0.6302 | 0.5835 | 0.5403 | 0.5002 | 0.4632 | 0.4289 | 0.3971 | |||
Present Value | -1,656 | - | -86 | -159 | -221 | -272 | -315 | -350 | -378 | -400 | -417 | -429 | 1,549 | -1,478 | ||
Step 4 | Analysis | |||||||||||||||
Total Outflow for A | ||||||||||||||||
Initial Investment | -10,000 | |||||||||||||||
Maintainace | -1,656 | |||||||||||||||
-11,656 | ||||||||||||||||
Equal per annum (-11,656/4) | -2,914 | |||||||||||||||
Total Outflow for B | ||||||||||||||||
Initial Investment | -20,000 | |||||||||||||||
Maintainace | -1,478 | |||||||||||||||
-21,478 | ||||||||||||||||
Equal per annum (-21,478/12) | -1,790 | |||||||||||||||
Advise | As per the analysis, a company must invest in Machine B since the Equalized NPV for the machine B is lower than Machine A |