Question

In: Biology

The Black Langshan chicken breed has feathered legs. When Black Langshan chickens are crossed with Bluff...

The Black Langshan chicken breed has feathered legs. When Black Langshan chickens are crossed with Bluff Rock chickens, which have unfeathered legs, all F1 has feathered legs. In the F2 only 24 out of 360 individuals have unfeathered legs while 336 chickens have feathered legs. (a) What type of gene interaction controls this phenotype? (b) Test your hypothesis using chi-square analysis.

Expert Solution

Answer :

According to question, crossing of feathered and unfeathered leg chicken produces F1 in which all have feathered legs. However, in F2, out of 360, we have 336 feathered leg chicken and 24 chicken with unfeathered legs.

Ratio of each phenotype in F2:

Proportion of Feathered leg-

= 336/360

=0.933

Proportion of unfeathered leg-

=24/360

=0.067

Ratio of the two will be approximately 15:1.

(a) Type of gene interaction: Duplicate dominant epistatic interaction .

Note:

In such type of gene interaction, the alleles of both gene loci produce the same phenotypic effect. For example, if there are two loci A and B, with alleles A, a and B, b, then all genotypes with at least one of the dominant alleles (either A Or B) will produce feathered legs. This means, A_B_, A_bb, aaB_ genotypes will have feathered legs. Only aabb chicken will be born with unfeathered legs.

Here, the parental cross would be AABB (feathered) × aabb (unfeathered), such that F1 would be AaBb (all feathered). F2 will include offsprings of AaBb self cross. The original 9:3:3:1 ratio would become 15:1.

(b) Chi square analysis:

gladiator answered 1 hour ago

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