y''+y=2t+1+(cos(t))^-2

Expert Solution

Colby Messinger answered 2 years ago

Solve using Laplace Transform: 1) y'' - 2y' + 5y = cos(2t) - cos(2t)u4pi(t); y(0) =...

Solve using Laplace Transform: 1) y'' - 2y' + 5y = cos(2t) - cos(2t)u4pi(t); y(0) = 0, y'(0) = 0

Consider the helix r(t)=(cos(2t),sin(2t),−3t)r(t)=(cos(2t),sin(2t),−3t). Compute, at t=π/6 A. The unit tangent vector T=T= ( , ,...

Consider the helix r(t)=(cos(2t),sin(2t),−3t)r(t)=(cos(2t),sin(2t),−3t). Compute, at t=π/6 A. The unit tangent vector T=T= ( , , ) B. The unit normal vector N=N= ( , , ) C. The unit binormal vector B=B= ( , , ) D. The curvature κ=κ=

Consider the spiral path x(t) = (cos^2t,sin^2t,t) for 0 ≤ t ≤ π/2. Evaluate the integral...

Consider the spiral path x(t) = (cos^2t,sin^2t,t) for 0 ≤ t ≤ π/2. Evaluate the integral x dx−y dy + z^2 dz

Solve the following initial value: y ''+ 4y = 2 cos 2t, y(0) = −2 and...

Solve the following initial value: y ''+ 4y = 2 cos 2t, y(0) = −2 and y 0 (0) = 0

Given r(t) = <2 cos(t), 2 sin(t), 2t>. • What is the arc length of r(t)...

Given r(t) = <2 cos(t), 2 sin(t), 2t>. • What is the arc length of r(t) from t = 0 to t = 5. SET UP integral but DO NOT evaluate • What is the curvature κ(t)?

Solve equations 1.) y'-y=t/y 2.) y'-(1/t)y=y2sin(t) 3.) y'+y=y2cos(t) 4.) y'-2y=cos(t)/(y1/2)

x' = -3x + 2y, y' = -10x + 5y +2e^t/cos 2t Solve the system by...

x' = -3x + 2y, y' = -10x + 5y +2e^t/cos 2t Solve the system by variation of parameters

Determine whether it is linear or nonlinear system: 1. y(t) = 3 + x(2t) 2. y(t)...

Determine whether it is linear or nonlinear system: 1. y(t) = 3 + x(2t) 2. y(t) = x(4t) 3. y(t) = -4t[x(2t)] 4. y(t) = e^2[x(2t)] 5. y(t) = x^5(t) 6. y(t) = cost[x(2t)]

For this parametrized curve: x = e^(2t) sin t , y = cos(4t) find tangent line...

For this parametrized curve: x = e^(2t) sin t , y = cos(4t) find tangent line to curve when t=1

a) ty’ −y/(1+T) = T,(T>0),y(1)=0 b) y′+(tanT)y=(cos(T))^2,y(0)=π2 Solve the above equations.

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