How much ice would I need to keep 887 mL of water at 0°C for 30...

How much ice would I need to keep 887 mL of water at 0°C for 30 min where the room temperature is 23°C.

Expert Solution

Density of water=0.9998g/cm3 at 0C

Mass of water=density*volume=0.9998g/cm3 * 887 cm3=886.823 g

Temperature=23K=273+23=296K

Heat (lost by water)=mass of water(mW) *specific heat of water(Cw)*change of temperature(296-273)K

=886.823 g*4.178 J/g K*(296-273)K

=85218.37 J=85.218KJ

Heat (gained by ice)=mass of ice* heat of fusion(Hf)

Hf=334.4 J/g

At thermal equilibrium,

Heat (lost by water)= Heat (gained by ice)

85.218 KJ=mass of ice*334.4 J/g

Mass of ice=85.218kj/0.3344 j/g=254.83 g (answer)

queen_honey_blossom answered 2 years ago

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