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What is the molarity of Mg(NO3)2 in a solution resulting from mixing 150 mL of 0.020...

What is the molarity of Mg(NO3)2 in a solution resulting from mixing 150 mL of 0.020 M HNO3 with 150 mL of 0.010 M Mg(OH)2?

Solutions

Expert Solution

HNO3 millimoles = 150 x 0.020 = 3

Mg(OH)2 millimoles = 150 x 0.01 = 1.5

2HNO3 + Mg (OH)2 ----------------------------> Mg(NO3)2 + 2H2O

3               1.5                                                    0                    0 -----------------------> initial

0                 0                                                     3                     3 ----------------------> after reaction

millimoles of Mg(NO3)2 = 3

molarity of Mg(NO3)2 = 3 / total volume

                                    = 3 / (150+150)

                                    = 3 /300

                                     = 1/100

                                     = 0.01 M

Mg(NO3)2 molarity = 0.01 M

queen_honey_blossom answered 1 year ago
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