In: Chemistry
If we want to prepare 150 mL of Acetic acid (C2H4O2) solution with the molarity of 0.20 M. How many grams of acetic acid do we need?
molarity of acetic acid = 0.2M
volume of acetic acid = 150ml = 0.15L
no of moles of acetic acid = molarity* volume in L
= 0.2*0.15 = 0.03 moles
molar mass of acetic acid = 60g/mole
mass of acetic acid = no of moles * gram molar mass
= 0.03*60 = 1.8g >>>>>answer