If we want to prepare 150 mL of Acetic acid (C2H4O2) solution with the molarity of...

If we want to prepare 150 mL of Acetic acid (C2H4O2) solution with the molarity of 0.20 M. How many grams of acetic acid do we need?

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Expert Solution

molarity of acetic acid = 0.2M

volume of acetic acid = 150ml = 0.15L

no of moles of acetic acid = molarity* volume in L

= 0.2*0.15 = 0.03 moles

molar mass of acetic acid = 60g/mole

mass of acetic acid = no of moles * gram molar mass

= 0.03*60 = 1.8g >>>>>answer

queen_honey_blossom answered 1 year ago

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