Two 4.0-cm-diameter disks face each other, 2.0mm apart. They are charged to

Expert Solution

Proton is moving from negative plate to positive plate. so, electric force on the proton is equal to the force on the proton. so,

Eq = ma

acceleration of the proton is ,

a = E q / m

= ( 9.9*10^ 5 N /C ) ( 1.6*10^ -19 C ) / ( 1.67*10 ^ -27 kg )

= 9.48*10^ 13 m/s^2

from kinematic equation of motion, vertical distance travelled by the proton is,

y = ( 1/ 2) a t ^2

time taken by the proton to travel a distance between the plates is ,

t = sqrt ( 2 h / a )

= sqrt ( 2 (2*10^ -3 mm ) / ( 9.48*10^ 13 m/s^2 )

= 6,49*10^- 9 s

Speed of proton is

v = d / t

= ( 2.0*10^ -3 m ) / ( 6.49*10^ -9 s)

= 3.0*10^ 5 m/s

genius_generous answered 2 years ago

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