Question

In: Chemistry

Experiment A B C intial rate of formation of D (M/min) 1 2.0 2.0 2.0 2.0...

Experiment

A

B C

intial rate of formation of D (M/min)

1 2.0 2.0 2.0 2.0
2 2.0 1.0 2.0 2.0
3 4.0 5.0 2.0 8.0
4 2.0 4.0 1.0 1.0
5 3.0 4.0 4.0 ?

a) Determine the rate law.

b) Calculate the rate constant. Specify units.

c) Calculate the rate of reaction for experiment 5.

d) How is the rate of appearance of D related to the disappearance of B?

e) In experiment 3, what is the rate of disappearance of B?

Solutions

Expert Solution

Let the rate expression be rD= K[A]m [ B]n [C]p

2.0 2.0             2.0 2.0                             

where   m,n,p are orders with respect to A, B, C respectively and K is rate constant

from First experiments

2= K [2]m [2]n [2]p     (1)

From second experiment

2= K [2]m [1]n [2]p     (2)

Dividing 1 and 2 gives

1= 2n   , n= 0

The rate expression becomes rD= K[A]m [C]p

from 3rd experiment   8=K [ 4]m [2]p    (3)

dividing 3 and 1 gives

4= (4/2)m ,     m= 2

From experiment 4

2.0            4.0             1.0 1.0

1= K[ 2]2 [ 1]p     (4)

Dividing 4 and 1 gives

2= [2]p   , p= 1

From 1

2= K[2]2 [ 2]1 K= 0.25

The rate expression then becomes

rD= 0.25 [ A]2 [C]1

The units of rate constant can be seen as

M/sec= Rate constant* [M]3

M= molarity

Rate constant = /M2.sec

following data refer to the reaction: A + 2B + C --> D + 2E

for the last experiment where A= 3 and C= 4

rD= 0.25*[3]2*4= 0.25*9*4= 9M/sec

A + 2B + C --> D + 2E

-rB/2= rD/1

Where 2 and 1 are coefficients of B and D in the reaction

In the 3rd experiments

-rB/2= rD/1= 8

-rB= 16 M/Sec.


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