Question

In: Biology

If the rate of product formation is 33μM/min at a substrate concentration of 10 mM, and...

If the rate of product formation is 33μM/min at a substrate concentration of 10 mM, and the enzyme is 50% saturated at a substrate concentration of 20mM, the Vmax of the enzyme is: :

A. 10μM/min B. 33μM/min C. 67μM/min D. 99μM/min E. 30mM/min

Solutions

Expert Solution

The correct option is D (99 µM/min)

As per Michaelis menten equation , The rate of a reaction can be calculated by the following formula

V= Vmax[s]/Km+S

Where Vmax is maximum velocity of reaction- Which has to be calculated

[S]- substrate concentration= 10 mM (Given)

Km- The substrate concentration when reaction attains half of it’s maximum velocity. In other words the concentration when 50% of enzyme is saturated with substrate= 20mM (Given).

V= initial velocity of reaction = 33µM/min

Now, let us put these values in the equation

We should change the mM units into µM by multiplying with 103

V= Vmax[s]/Km+S

33µM/min= Vmax X [10x103µM] / 20x 103 µM+10x103µM

Now we will do the cross multiplication

Vmax X [10x103µM]= 33µM/min X 20x 103 µM + 33µM/min X 10x103µM

Vmax X [10x103µM]= 660 x 103 µM /min+ 330 x 103 µM/min

Vmax X [10x103µM]=990 x103 µM/min

Vmax= 990 x103 µM / 10x103µM] (Division)

Vmax= 99 µM/min

Hence the correct option is D.

other options like A,B,C and E are incorrect.

gladiator answered 1 year ago
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