In: Biology
If the rate of product formation is 33μM/min at a substrate concentration of 10 mM, and the enzyme is 50% saturated at a substrate concentration of 20mM, the Vmax of the enzyme is: :
A. 10μM/min B. 33μM/min C. 67μM/min D. 99μM/min E. 30mM/min
The correct option is D (99 µM/min)
As per Michaelis menten equation , The rate of a reaction can be calculated by the following formula
V= Vmax[s]/Km+S
Where Vmax is maximum velocity of reaction- Which has to be calculated
[S]- substrate concentration= 10 mM (Given)
Km- The substrate concentration when reaction attains half of it’s maximum velocity. In other words the concentration when 50% of enzyme is saturated with substrate= 20mM (Given).
V= initial velocity of reaction = 33µM/min
Now, let us put these values in the equation
We should change the mM units into µM by multiplying with 103
V= Vmax[s]/Km+S
33µM/min= Vmax X [10x103µM] / 20x 103 µM+10x103µM
Now we will do the cross multiplication
Vmax X [10x103µM]= 33µM/min X 20x 103 µM + 33µM/min X 10x103µM
Vmax X [10x103µM]= 660 x 103 µM /min+ 330 x 103 µM/min
Vmax X [10x103µM]=990 x103 µM/min
Vmax= 990 x103 µM / 10x103µM] (Division)
Vmax= 99 µM/min
Hence the correct option is D.
other options like A,B,C and E are incorrect.