Question
In: Chemistry
For the minimum and maximum allowed pH values of blood, calculate the following ratios (you may...
For the minimum and maximum allowed pH values of blood, calculate the following ratios (you may use relevant Ka values that are tabulated for 25C in Appendix D of your textbook):
[Species #1] / [Phosphoric Acid]
[Species #2] / [Phosphoric Acid]
[Species #3] / [Phosphoric Acid]
Appendix D says: Phosphoric Acid H3PO4 Ka1 7.5 x 10 ^ -3 Ka2 6.2 x 10 ^-8 Ka3 4.2 x 10 ^-13
Solutions
Expert Solution
pH of blood ranges from 7.35 to 7.45
Using pH = 7.35
pH = pKa1 + log( [Species #1] / [Phosphoric Acid] )
7.35 = pKa1 + log[Species #1] / [Phosphoric Acid]
7.35 = 2.125 + log[Species #1] / [Phosphoric Acid]
[Species #1] / [Phosphoric Acid] = 10^5.225 = 1.68 x 10^5
pH = pKa2 + log [Species #2] / [Phosphoric Acid]
7.35 = pKa2 + log [Species #2] / [Phosphoric Acid]
7.35 = 7.207 + log [Species #2] / [Phosphoric Acid]
[Species #2] / [Phosphoric Acid] = 10^0.143 = 1.39
pH = pKa3 + log [Species #3] / [Phosphoric Acid]
7.35 = 12.38 + log [Species #3] / [Phosphoric Acid]
[Species #3] / [Phosphoric Acid] = 10^(-5.03) = 9.33 x 10^-6
With pH = 7.45
pH = pKa1 + log( [Species #1] / [Phosphoric Acid] )
7.45 = 2.12 + log( [Species #1] / [Phosphoric Acid] )
( [Species #1] / [Phosphoric Acid] ) = 10^5.33 = 2.14 x 10^5
pH = pKa2 + log [Species #2] / [Phosphoric Acid]
7.45 = 7.207 + log [Species #2] / [Phosphoric Acid]
[Species #2] / [Phosphoric Acid] = 1.747
pH = pKa3 + log [Species #3] / [Phosphoric Acid]
7.45 = 12.38 + log [Species #3] / [Phosphoric Acid]
[Species #3] / [Phosphoric Acid] = 1.18 x 10^-5
queen_honey_blossom answered 1 year agoRelated Solutions
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