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In: Chemistry

For the minimum and maximum allowed pH values of blood, calculate the following ratios (you may...

For the minimum and maximum allowed pH values of blood, calculate the following ratios (you may use relevant Ka values that are tabulated for 25C in Appendix D of your textbook):

[Species #1] / [Phosphoric Acid]

[Species #2] / [Phosphoric Acid]

[Species #3] / [Phosphoric Acid]

Appendix D says: Phosphoric Acid H3PO4 Ka1 7.5 x 10 ^ -3 Ka2 6.2 x 10 ^-8 Ka3 4.2 x 10 ^-13

Solutions

Expert Solution

pH of blood ranges from 7.35 to 7.45

Using pH = 7.35

pH = pKa1 + log( [Species #1] / [Phosphoric Acid] )

7.35 = pKa1 + log[Species #1] / [Phosphoric Acid]

7.35 = 2.125 + log[Species #1] / [Phosphoric Acid]

[Species #1] / [Phosphoric Acid] = 10^5.225 = 1.68 x 10^5

pH = pKa2 + log [Species #2] / [Phosphoric Acid]

7.35 = pKa2 + log [Species #2] / [Phosphoric Acid]

7.35 = 7.207 + log [Species #2] / [Phosphoric Acid]

[Species #2] / [Phosphoric Acid] = 10^0.143 = 1.39

pH = pKa3 + log [Species #3] / [Phosphoric Acid]

7.35 = 12.38 + log [Species #3] / [Phosphoric Acid]

[Species #3] / [Phosphoric Acid] = 10^(-5.03) = 9.33 x 10^-6

With pH = 7.45

pH = pKa1 + log( [Species #1] / [Phosphoric Acid] )

7.45 = 2.12 + log( [Species #1] / [Phosphoric Acid] )

( [Species #1] / [Phosphoric Acid] ) = 10^5.33 = 2.14 x 10^5

pH = pKa2 + log [Species #2] / [Phosphoric Acid]

7.45 = 7.207 + log [Species #2] / [Phosphoric Acid]

[Species #2] / [Phosphoric Acid] = 1.747

pH = pKa3 + log [Species #3] / [Phosphoric Acid]

7.45 = 12.38 + log [Species #3] / [Phosphoric Acid]

[Species #3] / [Phosphoric Acid] = 1.18 x 10^-5

queen_honey_blossom answered 2 years ago
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