Question

In: Physics

A horizontal pipe carries a smoothly flowing liquid with density 1.39 × 103 kg/m3. At locations...

A horizontal pipe carries a smoothly flowing liquid with density 1.39 × 103 kg/m3. At locations 1 and 2 along the pipe the diameters are 5.23 cm and 2.19 cm, respectively. The flow speed at location 1 is 1.79 m/s. What is the pressure difference between location 2 and location 1 (including its sign)? Ignore viscosity.

Solutions

Expert Solution

Gravitational acceleration = g = 9.81 m/s2

Density of the fluid = = 1390 kg/m3

Diameter of pipe at location 1 = D1 = 5.23 cm = 0.0523 m

Diameter of pipe at location 2 = D2 = 2.19 cm = 0.0219 m

Area of pipe at location 1 = A1

A1 = D12/4

Area of pipe at location 2 = A2

A2 = D22/4

Flow speed of fluid at location 1 = V1 = 1.79 m/s

Flow speed of fluid at location 2 = V2

By continuity equation,

A1V1 = A2V2

(D12/4)V1 = (D22/4)V2

D12V1 = D22V2

(0.0523)2(1.79) = (0.0219)2V2

V2 = 10.208 m/s

Pressure of fluid at location 1 = P1

Pressure of fluid at location 2 = P2

The pipe is horizontal, therefore the height of the pipe at location 1 and 2 is same.

Pressure difference between location 2 and location 1 = P = P2 - P1

By Bernoulli's Equation,

P = -70194.42 Pa

Pressure difference between location 2 and location 1 = -70194.42 Pa


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