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In: Physics

A four legged sling distributes its load equally among its four legs. When the load is...

A four legged sling distributes its load equally among its four legs. When the load is picked up, each leg forms 45° with the horizontal. The nominal breaking strength of the chain is specified to be 10 tons. If the load that is carried is 5 tons, Would it be safe to carry the load? What factors might play a role in setting 20% as the safety factor?

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Expert Solution

The nominal breaking strength of the chain is the maximum safe force can exert to lift, suspend, or lower, a given mass without fear of breaking. Let the breaking strength is F of one leg of a sling, and when the load is picked up, each leg forms 45° with the horizontal. Hence, the opposite two chain of the sling will be in perpendicular position i.e. the angle between two will be 90o. The resultant force will act vertically downward direction and the resultant will be . The resultant for other two chain will be also . The net vertically downward force will be 2R or . If the breaking strength of a chain is 10 tons (F), then the four leg sling can carry a maximum load of or 28.28 tons.

Therefore, if the load that is carried is 5 tons,it is safe to carry the load.

The factors like the material properties, thickness of chain material etc. may play role to determine the breaking strength of the chain and its maximum breaking strength. The elastic properties of the material play an important role for these purpose. Within elastic limit the chain will stretch and come to its initial position without any elastic fatigue. Below, an example of rating calculation for this problem:

Chains have a working load limit- or WLL- of approximately one third of their break strengths (the amount of force the chains can withstand before they break) i.e. 1/3 of 10 tons or 3.33 tons. Hence, the four leg sling can carry a maximum load of or 9.42 tons. The 20 % of it will be 9.42 x 20/100 or 1.88 tons. The safe limit of the carrying load is (9.42 - 1.88) or 7.54 tons.

genius_generous answered 3 hours ago
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