In: Statistics and Probability
A telephone company claims that the service calls which they receive are equally distributed among the five working days of the week. A survey of 8181 randomly selected service calls was conducted. Is there enough evidence to refute the telephone company's claim that the number of service calls does not change from day-to-day?
Days of the Week | Mon | Tue | Wed | Thu | Fri |
---|---|---|---|---|---|
Number of Calls | 18 | 14 | 12 | 18 | 19 |
Step 1 of 10: State the null and alternative hypothesis. |
Choice 1:
H0: Service calls are equally distributed over the five working days.
Ha: Service calls are not equally distributed over the five working days.
Choice 2:
H0H0: Service calls are not equally distributed over the five working days.
HaHa: Service calls are equally distributed over the five working days.
Step 2 of 10:
What does the null hypothesis indicate about the proportions of service calls received each day?
Choice 1: The proportions of service calls received each day are
all thought to be equal
Choice 2: The proportions of service calls received each day are
different for each category (and equal to the previously accepted
values).
Step 3 of 10:
State the null and alternative hypothesis in terms of the expected proportions for each category.
H0: Pi = ______
Ha: There is some difference amongst the proportions.
Step 4 of 10:
Find the expected value for the number of service calls received on Monday. Round your answer to two decimal places.
Step 5 of 10:
Find the expected value for the number of service calls received on Friday. Round your answer to two decimal places.
Step 6 of 10:
Find the value of the test statistic. Round your answer to three decimal places.
Step 7 of 10:
Find the degrees of freedom associated with the test statistic for this problem.
Step 8 of 10:
Find the critical value of the test at the 0.01 level of significance. Round your answer to three decimal places.
Step 9 of 10:
Make the decision to reject or fail to reject the null hypothesis at the 0.01 level of significance.
Choice 1: Fail to Reject Null Hypothesis
Choice 2:Reject Null Hypothesis
Step 10 of 10:
State the conclusion of the hypothesis test at the 0.01 level of significance.
Choice 1: There is not enough evidence to refute the claim that the
service calls are distributed evenly among the days.
Choice 2: There is enough evidence to refute the claim that the service calls are distributed evenly among the days.
>> Step 1 of 10: The null and alternative hypothesis:
Choice 1:
H0: Service calls are equally distributed over the five working days.
Ha: Service calls are not equally distributed over the five working days.
>> Step 2 of 10: The null hypothesis indicate:
Choice 1: The proportions of service calls received each day are all thought to be equal.
>> Step 3 of 10: The null and alternative hypothesis in terms of the expected proportions for each category:
H0: Pi = 0.20
Ha: There is some difference amongst the proportions.
>> Step 4 of 10: The expected value for the number of service calls received on Monday
= 16.20
>> Step 5 of 10: The expected value for the number of service calls received on Friday
= 16.20
>> Step 6 of 10: The value of the test statistic
= 2.272
>> Step 7 of 10: The degrees of freedom associated with the test statistic for this problem
= 4
>> Step 8 of 10: The critical value of the test at the 0.01 level of significance
= 13.277
>> Step 9 of 10: The decision to reject or fail to reject the null hypothesis at the 0.01 level of significance:
Choice 1: Fail to Reject Null Hypothesis.
>> Step 10 of 10: The conclusion of the hypothesis test at the 0.01 level of significance:
Choice 1: There is not enough evidence to refute the claim that the service calls are distributed evenly among the days.
CALCULATIONS: