A proud deep-sea fisherman hangs a 61.0-kg fish from an ideal spring having negligible mass. The...

A proud deep-sea fisherman hangs a 61.0-kg fish from an ideal spring having negligible mass. The fish stretches the spring 0.130 m.

(a) Find the force constant of the spring.
N/m

The fish is now pulled down 4.90 cm and released.

(b) What is the period of oscillation of the fish?
s

(c) What is the maximum speed it will reach?
m/s

Expert Solution

At equilibroum position , weight = restoring force

mg = kx

From this force constant k = mg / x

= 4598.46 N / m

(2). Period of oscillations T = 2??[ m / k ]

= 0.724 s

genius_generous answered 1 hour ago

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