In: Physics
An automobile has a vertical antenna 1.40 m long. The automobile travels eastward at 65 km/h on a horizontal road where the Earth's magnetic field is 50.2
Giventhat the length of the antena is L = 1.40 m
the velocityof the auto mobile is v = 65.0 Km/h =65.0 Km/hr (1m /10-3Km)(1hr/ 3600s)
= 18.06 m/s
the earths magnetic field is B = 50.2?T =50.2*10-6 T
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if the top of the antenna positive relativeto the bottom , for aximum antenna
F = q(v ? B)
so the auto must movetowards east because angle is 90degrees
? =B*L*v
= ( 50.2*10-6 T )*(1.40 m )(18.06 m/s)sin 65.50
= 1.155*10^-3 V