In: Physics
1)An outdoor circular fish pond has a diameter of 4.00 m and a uniform full depth of 1.40m . A fish halfway down in the pond and 0.70m from the near side can just see the full height of a 1.80m tall person.How far away from the edge of the pond is the person?
2)Two people stand 5.2m apart and 3.1m away from a large plane mirror in a dark room. At what angle of incidence should one of them shine a flashlight on the mirror so that the reflected beam directly strikes the other person?
3)A beam of light is incident on a plane mirror at an angle of 41? relative to the normal.What is the angle between the reflected ray and the surface of the mirror?
Above mentioned questions were resolved before with different figures. Please input your figure to get your answer. Let me know if you face any issue. Please rate if I succeeded in helping you
1) An outdoor circular fish pond has a diameter of 4.0m and a uniform full depth of 1.5m. A fish halfway down in the pond and 0.5m from the near side can just see the full height of a 1.8m tall person. How far away from the edge of the pond is the person?
f = R/2 = D/4 = 4/4 = 1m
u= 0.5
so 1/f = 1/u +1/v
v = uf/(u-f)
v = 0.5* 1/(0.5-1)
v = -1 m
now apply snells law na sinA = nb sin B
na= 1.33 and nb =1
sin A = 0.4203 deg
apparent depth 1.8/X= 2.156
X = 1.8/2.16
X = 83 cm
2) Twopeople stand 3.8 m away froma large plane mirror and spaced 4.6 m apart in a dark room. At what angle ofincidence should one of them shine a flashlight on the mirror sothat the reflected beam directly strikes the other person?

from the diagram:
the angle of incidence
? = arctan(2.3m/3.8m)
= 31.2deg
the angle of incidence should be 31.2deg
3) A beam of light is incident on a plane mirror at an angle of 30 degrees to the normal of the mirror. What is the angle between the incident beam and reflected beam?
Angle of reflection equals angle of incidence, so the light is reflected at 30 degrees relative to the normal. Since the normal is perpendicular to the surface of the miirror, the angle between the reflected rays and the mirror is 90 degrees minus 30 degrees, or 60 degrees.