In: Physics
a 4.00 kg mass is moving in a circular path of radius 3.20 m with a constant linear speed of 6.29 m/s. The radial force on the mass is
Information provided- mass=m=4.00 kg
Radius=R=3.20 m
linear speed=v=6.29 m/s
concept to be used-curvilinear motion.
When a body moves in a curved path its velocity changes both in
magnitude and direction giving rise to two components of
acceleration namely
and
.
is the component of acceleration due to change in direction of
velocity.
=v2/R
in magnitude and acts radially towards the centre.
=
dv/dt in magnitude and acts in the direction of v (if velocity
increases with time)
In this question the body is moving with a constant linear
velocity v so making the
=0 (as derivative of a constant is zero)
let
be the total acceleration .
as
=0
=v2/R
and directed towards the centre.
=6.292/3.2=12.364
m/s2
we know F=ma=m=4.00x12.364=49.456
N and direction of the force is towards the centre.(in the
direction of acceleration)
The radial force on the mass is 49.456 N.