Calculate the [H3O+] of the following polyprotic acid solution: 0.400 M H3PO4.

Expert Solution

Solution :-

ka1 = 7.2*10^-3

ka2 = 6.3*10^-8

ka3 = 4.2*10^-13

lets write the equation of the H3PO4 in water

H3PO4 + H2O ------ > H3O+ + H2PO4^-

0.400 0 0

-x +x +x

0.400-x x x

ka1 = [H3O+] [H2PO4^-]/[H3PO4]

7.2*1^-3 = [x][x]/[0.400-x]

7.2*10^-3 *0.400-x =x^2

solving for the x we get

0.0502 = x

so the concentration of the H3O+ from the ka1 = 0.0502 M

the ka2 and ka3 values are very small therefore it will not add much to the H3O+ concentration

Therefore the concentration of the H3O+ = 0.0502 M

queen_honey_blossom answered 5 hours ago

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