Question

In: Statistics and Probability

Consider the np-chart for n=50, LCL=1.515, and UCL=18.485. Derive the β-risk as a function of p...

Consider the np-chart for n=50, LCL=1.515, and UCL=18.485.

Derive the β-risk as a function of p and derive the approximate β-risk by the normal approximation.

Draw the OC curve under p0, two negative shifts of p, and two positive shifts of p

Solutions

Expert Solution

Now the oc curve for the shifts are

The R code for obtaining of curve:

p=c(.05,.1,.2,.4,.6)

beta_risk=pnorm(18.485,50*p,50*p*(1-p))-pnorm(1.515,50*p,50*p*(1-p))

plot(p,beta_risk,type="l",main="oc curve")


Related Solutions

Define the "center line", "LCL" and "UCL" for an p chart and a p bar chart.
Define the "center line", "LCL" and "UCL" for an p chart and a p bar chart.
1. What is the UCL for the XBar chart based on the data below, with n=4,...
1. What is the UCL for the XBar chart based on the data below, with n=4, and ten set of samples for the weight of soft drinks are given. USL for the product is 355 g and LSL is 345. Daily production is 15000 units. Sample # Observations 1 352 348 350 351 2 351 352 351 350 3 351 346 342 350 4 349 353 352 352 5 351 350 351 351 6 353 351 346 346 7 348...
If np ≥5 and nq ≥​5, estimate P (at least 7) with n =13 and p=0.6...
If np ≥5 and nq ≥​5, estimate P (at least 7) with n =13 and p=0.6 by using the normal distribution as an approximation to the binomial​ distribution; if np <5 or nq <​5, then state that the normal approximation is not suitable. Select the correct choice below​ and, if​ necessary, fill in the answer box to complete your choice. A. P (at least 7) = ​(Round to three decimal places as​ needed.) B. The normal distribution cannot be used.
The following xbar and s charts based on n=4 have shown statistical control: Xba Chart: UCL=710,...
The following xbar and s charts based on n=4 have shown statistical control: Xba Chart: UCL=710, CL=700, LCL=690, s chart- UCL=18.08, CL=7.979, LCL=0, A)Estimate the process parameters mean and sigma (standard deviation). B)If the specifications are at 705+/-15, and the process output is normally distributed, estimate the fraction non conforming. C)For the Xbar chart, find the probability of a type I error, assuming sigma is constant. D)Suppose the process mean shifts to 693 and the standard deviation simulatneously shifts to...
If np ≥ 5 and nq ≥ 5​, estimate P(fewer than 3) with n =14 and...
If np ≥ 5 and nq ≥ 5​, estimate P(fewer than 3) with n =14 and p = 0.4 by using the normal distribution as an approximation to the binomial​ distribution; if np < 5 or nq <​ 5, then state that the normal approximation is not suitable. Select the correct choice below​ and, if​ necessary, fill in the answer box to complete your choice. A. P(fewer than 3)= or B. the normal approximation is not suitable
QQQ3 When large samples (np > 5 and n(1 - p) > 5) are associated with...
QQQ3 When large samples (np > 5 and n(1 - p) > 5) are associated with hypothesis tests for a single population proportion, then the associated test statistic will be is a z-score. True or false? QQQ7 In the P-value approach to hypothesis testing, if the P-value is less than a specified significance level, then we fail to reject the proposed null hypothesis. QQQ10 A Type I error is the error made in failing to reject an incorrect null hypothesis....
If np >= 5 and nq >= 5​, estimate Upper P( fewer than 6) with n...
If np >= 5 and nq >= 5​, estimate Upper P( fewer than 6) with n =13 and p= 0.5 by using the normal distribution as an approximation to the binomial​ distribution; if np < 5 or nq < 5, then state that the normal approximation is not suitable. P(fewer than 6) = ?
Let X be a Bin(n, p) random variable. Show that Var(X) = np(1 − p). Hint:...
Let X be a Bin(n, p) random variable. Show that Var(X) = np(1 − p). Hint: First compute E[X(X − 1)] and then use (c) and (d). (c) Var(X) = E(X^2 ) − (E X)^ 2 (d) E(X + Y ) = E X + E Y
Write the total differential for H as a function of T & P and derive the...
Write the total differential for H as a function of T & P and derive the appropriate working equation.
Using the normal distribution, calculate the following probabilities: a) P(X≤16|n=50, p=0.70) b) P(10≤X≤16|n=50, p=0.50)
Using the normal distribution, calculate the following probabilities: a) P(X≤16|n=50, p=0.70) b) P(10≤X≤16|n=50, p=0.50)
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT