Question

In: Advanced Math

Suppose that a graph G is such that each vertex of G has degree at least...

Suppose that a graph G is such that each vertex of G has degree at least 100. Show that G contains a cycle of length at least 101, i.e., a cycle passing through at least 101 vertices.

Solutions

Expert Solution

Here a graph G(V, E) is such that each vertex of G has degree at least 100. it means that G has at least 101 vertices.

so we make cases

Case-I ) If G has 101 vertices & degree of each vertex is 100 ,So G become complete graph.

We know complete graph has a cycle contain 101 vertex has i.e G contain a cycle of length at least 101.

Case-II) If No. of vertex(V) in G has greater than 101 vertices.

[Note : If no. of vertex is less than 101 then graph G does not exist which contain degree of each vertex has 100.]


Related Solutions

We say a graph is k-regular if every vertex has degree exactly k. In each of...
We say a graph is k-regular if every vertex has degree exactly k. In each of the following either give a presentation of the graph or show that it does not exist. 1) 3-regular graph on 2018 vertices. 2) 3-regular graph on 2019 vertices.
(a) What is the maximum degree of a vertex in a simple graph with n vertices?...
(a) What is the maximum degree of a vertex in a simple graph with n vertices? (b) What is the maximum number of edges in a simple graph of n vertices? (c) Given a natural number n, does there exist a simple graph with n vertices and the maximum number of edges?
find an alternative  definition of the degree of a vertex of a graph.  please be detailed...
find an alternative  definition of the degree of a vertex of a graph.  please be detailed as possible thank you
A tree is a circuit-free connected graph. A leaf is a vertex of degree 1 in...
A tree is a circuit-free connected graph. A leaf is a vertex of degree 1 in a tree. Show that every tree T = (V, E) has the following properties: (a) There is a unique path between every pair of vertices. (b) Adding any edge creates a cycle. (c) Removing any edge disconnects the graph. (d) Every tree with at least two vertices has at least two leaves. (e) | V |=| E | +1.
Prove that any graph where every vertex has degree at most 3 can be colored with...
Prove that any graph where every vertex has degree at most 3 can be colored with 4 colors.
Suppose you have an all positive edge-weighted graph G and a start vertex a and asks...
Suppose you have an all positive edge-weighted graph G and a start vertex a and asks you to find the lowest-weight path from a to every vertex in G. Now considering the weight of a path to be the maximum weight of its edges, how can you alter Dijkstra’s algorithm to solve this?
Prove or disprove: If G = (V; E) is an undirected graph where every vertex has...
Prove or disprove: If G = (V; E) is an undirected graph where every vertex has degree at least 4 and u is in V , then there are at least 64 distinct paths in G that start at u.
Suppose G is a connected cubic graph (regular of degree 3) and e is an edge...
Suppose G is a connected cubic graph (regular of degree 3) and e is an edge such that G − e has two connected components G1 and G2 (a) Explain what connected means. (b) We say that e is a____________ of G (c) show that G1 has an odd number of vertices. (d) draw a connected cubic graph G with an edge e as above.
Given an undirected graph G=(V, E) with weights and a vertex , we ask for a...
Given an undirected graph G=(V, E) with weights and a vertex , we ask for a minimum weight spanning tree in G where is not a leaf (a leaf node has degree one). Can you solve this problem in polynomial time? Please write the proof.
Discrete Mathematics A tree contains 1 vertex of degree 2, 1 vertex of degree 3, 1...
Discrete Mathematics A tree contains 1 vertex of degree 2, 1 vertex of degree 3, 1 vertex of degree 4, 11 leaves and the remaining vertices have degree 3. Find the total number of vertices. Sketch two non-isomorphic trees statisfying the above mentioned conditions.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT