In: Operations Management
Amanda has a yearly advertising and promotions budget of $50,000. Her goal is to maximize the reach (the number of customers that see her company’s ads or other marketing efforts). She is considering a mix of placing ads on art websites and in printed art magazines, as well as using targeted social media ad placements and appearances at art tradeshows. She wants to make sure that the company has an online presence, so would like to see at least 100 ads placed in any combination of websites and social media per year. However, she has data that suggests that if she advertises on the websites more than 60 times per year she will be wasting money. There are seven art tradeshows that the company could attend, but Amanda feels it is mandatory to attend at least the two most popular tradeshows. There are three major art magazines, each published monthly, that Amanda would like to advertise in. She could advertise in each of these once per month but would be comfortable reducing the frequency to a minimum of once every three months in each magazine and rotating the placements between the magazines. The reach and cost of each type of ad placement or event is shown below: Art Websites Social Media Art Tradeshows Print Magazine Ads Reach (number of people) 20,000 10,000 5,000 15,000 Cost (dollars) 200 250 1,000 400 Recommend the appropriate mix of advertising and promotions for the company. Also comment on what would change if Amanda doubled her advertising and promotions budget. Estimate the increased reach.
Solution:
Let us assume that number of advertisements or events on each of the four channels are as follows:
Now it is given that reach and cost of each channel is as follows:
Advertising Channel |
Ads Reach (Number of People) |
Cost (Dollars) |
Art Websites |
20,000 |
200 |
Social Media |
10,000 |
250 |
Art Tradeshows |
5,000 |
1,000 |
Print Magazines |
15,000 |
400 |
Amanda’s objective is to maximize the reach. So, we can say that the goal is to –
Maximize z = (20,000 . a) + (10,000 . b) + (5,000 . c) + (15,000 . d)
Or we can rewrite it for thousands of people as follows:
Maximize z = 20.a + 10.b + 5.c + 15.d
Amanda has a yearly advertising and promotions budget of $50,000. Hence –
200.a + 250.b + 1000.c + 400.d ≤ 50000
» 4.a + 5.b + 20.c + 8.d ≤ 1000
Amanda would like to see at least 100 ads placed in any combination of websites and social media per year. Hence –
a + b ≥ 100
If she advertises on the websites more than 60 times per year she will be wasting money. Hence –
a ≤ 60
There are seven art tradeshows that the company could attend, but Amanda feels it is mandatory to attend at least the two most popular tradeshows. Hence –
c ≤ 7 and
c ≥ 2
There are three major art magazines, each published monthly. Hence –
d ≤ (3*12)
» d ≤ 36
Now Amanda is comfortable reducing the frequency to a minimum of once every three months in each magazine and rotating the placements between the magazines. Hence –
d ≥ (3*4)
» d ≥ 12
So, we can solve it using integer programming as follows:
Maximize z = 20.a + 10.b + 5.c + 15.d
Subject to
4.a + 5.b + 20.c + 8.d ≤ 1000
a + b ≥ 100
0 ≤ a ≤ 60
0 ≤ b
2 ≤ c ≤ 7
12 ≤ d ≤ 36
Now, solving it using excel solver, we would find following as the optimal mix –
a = 60, b = 124, c = 2, 12 ANSWER
Reach = (20*60) + (10*124) + (2*5) + (15*12) Thousands
= 2,630,000 ANSWER
Please observe that
Hence if we double the advertising budget. The optimal mix will be derived by changing following constraint-
4.a + 5.b + 20.c + 8.d ≤ 2000 (Doubled)
And the optimal mix in double budget would be –
a = 60, b = 324, c = 2, 12 (following the strategy of maximizing social media spend) ANSWER
And the increased Reach = (20*60) + (10*324) + (2*5) + (15*12) Thousands = 4,630,000 ANSWER