Question

A glass flask whose volume is 1000cm3 at a temperature of 1.00?C is completely filled with mercury at the same temperature. When the flask and mercury are warmed together to a temperature of 52.0?C , a volume of 8.35cm3 of mercury overflows the flask. If the coefficient of volume expansion of mercury is ?Hg = 1.80

Answer 1

Heated volume of Hg = Original volume of Hg{1 + }

Orginal volume of Hg = 1000 cm^3, =1.80 x 10^-4,

T1-T0 = change in temperature = 52-1= 51 C

Heated volume of Hg= 1000{ 1+ 1.80x10^-4 x 51}

heated volume of Hg= 1009.18 cubic centimeter

Heated volume of glass= Heated volume of Hg- amount of mercury overflowing

Heated volume of glass = 1009.18-8.35= 1000.83 cubic centimeter

Heated volume of glass=Original volume of glass { 1 + glass(T1-T0)}

1000.83 = 1000{ 1+(51)}

1.00083 = 1 + beta(51)

0.00083 = 51*beta

coefficient of expansion of glass = 0.00083/51

                                                 = 1.627 x 10^-5 /K