Question

In: Physics

A glass flask whose volume is 1000 cm3 at a temperature of 0.100 ∘C is completely...

A glass flask whose volume is 1000 cm3 at a temperature of 0.100 ∘C is completely filled with mercury at the same temperature. When the flask and mercury are warmed together to a temperature of 52.0 ∘C , a volume of 8.50 cm3 of mercury overflows the flask.

If the coefficient of volume expansion of mercury is βHg = 1.80×10⁻⁴ /K , compute βglass, the coefficient of volume expansion of the glass.

Expert Solution

Initial volume of the glass flask = Initial volume of mercury = V = 1000 cm³

Initial temperature of the flask and the mercury = T₁ = 0.1 ^oC

Final temperature of the flask and mercury = T₂ = 52 ^oC

Coefficient of volume expansion of mercury = _Hg = 1.8 x 10^-4 K^-1

Coefficient of volume expansion of glass = _glass

Change in volume of mercury = V₁

V₁ = V_Hg(T₂ - T₁)

V₁ = (1000)(1.8x10^-4)(52 - 0.1)

V₁ = 9.342 cm³

Volume of mercury that overflows the flask = V₁ = 8.5 cm³

Change in volume of the glass flask = V₂

V₂ = V₁ - V₁

V₂ = 9.342 - 8.5

V₂ = 0.842 cm³

V₂ = V_glass(T₂ - T₁)

0.842 = (1000)(_glass)(52 - 0.1)

_glass = 1.622 x 10^-5 K^-1

Coefficient of volume expansion of glass = 1.622 x 10^-5 K^-1

genius_generous answered 4 hours ago

Finding the volume of a flask. A student obtained a clean dry glass-stoppered flask.

1. Finding the volume of a flask. A student obtained a clean dry glass-stoppered flask. She weighed the flask and stopper on an analytical balance and found the total mass to be 31.601 g. She then filled the flask with water and obtained a mass for the full stoppered flask of 60.735 g. From these data, and the fact that at the temperature of the used water its density is 0.9973 g/cm3, find the volume of the stoppered flask....

An ice cube of volume 15 cm3 is initially at the temperature -20C . How much...

An ice cube of volume 15 cm3 is initially at the temperature -20C . How much heat is required to convert this ice cube into steam?

Wine bottles are never completely filled: a small volume of air is left in the glass...

Wine bottles are never completely filled: a small volume of air is left in the glass bottle's cylindrically shaped neck (inner diameter dd = 18.5 mmmm) to allow for wine's fairly large coefficient of thermal expansion. The distance H between the surface of the liquid contents and the bottom of the cork is called the "headspace height"(Figure 1), and is typically H = 1.5 cmcm for a 750-mLmL bottle filled at 20 ∘C∘C. Due to its alcoholic content, wine's coefficient...

Wyatt is designing a hollow cylindrical metal can with volume 1000 cm3. The material used to...

Wyatt is designing a hollow cylindrical metal can with volume 1000 cm3. The material used to make the circular top and bottom of the can costs twice as much as the material used to make the side of the can. What dimensions should Wyatt choose in order to minimize the cost of the can? Show all your work, round off the numerical part of your final answer to four (4) decimal places, and express your final answer in the form...

using the temperature of air, barometric pressure, and volume of flask, calculate moles of air for...

using the temperature of air, barometric pressure, and volume of flask, calculate moles of air for each trial. trial 1: temperature of air: 20.1 deg Celcius, barometric pressure: 742.44 Hg, volume of flask: 285 ml Trial 2: Temp of air 20.2 deg celcius. Barametric pressure: 742.44 Hg , volume : 285 ml

An 13 g ice cube at -13˚C is put into a Thermos flask containing 110 cm3...

An 13 g ice cube at -13˚C is put into a Thermos flask containing 110 cm3 of water at 18˚C. By how much has the entropy of the cube-water system changed when a final equilibrium state is reached? The specific heat of ice is 2200 J/kg K and that of liquid water is 4187 J/kg K. The heat of fusion of water is 333 × 103 J/kg.

An 7.5 g ice cube at −10°C is put into a Thermos flask containing 150 cm3...

An 7.5 g ice cube at −10°C is put into a Thermos flask containing 150 cm3 of water at 21°C. By how much has the entropy of the cube–water system changed when equilibrium is reached? The specific heat of ice is 2220 J/kg · K. (The latent heat of fusion for water is 333 kJ/kg.)

An 8.5 g ice cube at −10°C is put into a Thermos flask containing 150 cm3...

An 8.5 g ice cube at −10°C is put into a Thermos flask containing 150 cm3 of water at 30°C. By how much has the entropy of the cube-water system changed when equilibrium is reached? The specific heat of ice is 2220 J/kg · K. (The latent heat of fusion for ice is 333 kJ/kg and the specific heat of water is 4187 J/kg · K.)

For the exothermic reaction PCl3(g)+Cl2(g)?PCl5(g) Kp = 0.100 at a certain temperature. A flask is charged...

For the exothermic reaction PCl3(g)+Cl2(g)?PCl5(g) Kp = 0.100 at a certain temperature. A flask is charged with 0.500 atm PCl3 , 0.500 atm Cl2, and 0.300atm PCl5 at this temperature. What are the equilibrium partial pressures of PCl3 , Cl2, and PCl5, respectively? Express your answers numerically in atmospheres with three digits after the decimal point, separated by commas.

The temperature of 500 mL of distilled water in a flask is between 70°C and 90°C....

The temperature of 500 mL of distilled water in a flask is between 70°C and 90°C. Room temperature is 20°C. the useful range of the only thermometer available is between 0°C and 50°C. Briefly describe an experiment you could carry out which would allow you to determine exactly the temperature of the water in the flask. Indicate the following in your description: What equipment would you use? What would you do? The equation(s) for any calculation(s) you would carry out,...