Question
In: Math
Find the area under the graph of f over the interval left bracket 7 comma 9...
Find the area under the graph of f over the interval
left bracket 7 comma 9 right bracket[7,9].
f(x)equals=StartSet Start 2 By 2 Matrix 1st Row 1st Column 4 x plus 9 comma 2nd Column for x less than or equals 8 2nd Row 1st Column 81 minus 5 x comma 2nd Column for x greater than 8 EndMatrix
| 4x+9, | for x≤8 |
| 81−5x, | for x>8 |
The area is
nothing.
2)
Find the area of the region bounded by the graphs of the given equations.
yequals=x plus 6x+6,
yequals=x squaredx2
The area is
nothing.
(Type an integer or a simplified fraction.)
Solutions
Expert Solution
1) The two lines intersect when
4x+9 = 81−5x
9x = 72, i.e. x = 8
Since they intersect in the middle of given interval [7, 9] hence from 7 ≤ x ≤ 8 one line will be over the other, and in the other interval 8 ≤ x ≤ 9 it will be the other way round. This can also be shown in the sketch below.
Hence, the required area is
2) The two curves intersect when
Hence, we need to find area in the interval -2 ≤ x ≤ 3. In this intevral, the line is above the parabola. This can be sketvhed as below
Hence, the required area is
milcah answered 2 years agoRelated Solutions
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Sketch the area under the standard normal curve over the
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The area to the left of z = −1.35 is
The area to the left of z = 0.46 is
The area to the right of z = 1.41 is
The area to the right of z = −1.12 is
The area between z = 0 and z = 3.00 is
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Sketch the area under the standard normal curve over the indicated interval and find the specified...
Sketch the area under the standard normal curve over the
indicated interval and find the specified area. (Round your answer
to four decimal places.) The area to the right of z = −2.12 is
.
Sketch the area under the standard normal curve over the indicated interval and find the specified...
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indicated interval and find the specified area. (Round your answer
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2.10
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z = −1.85
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z = −0.13
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