Question

Sketch the area under the standard normal curve over the indicated interval and find the specified area. (Round your answer to four decimal places.)

The area to the left of z = −1.35 is

The area to the left of z = 0.46 is

The area to the right of z = 1.41 is

The area to the right of z = −1.12 is

The area between z = 0 and z = 3.00 is

The area between z = 0 and z = −1.81 is

The area between z = −2.12 and z = 1.32 is

The area between z = 0.26 and z = 1.84 is

The area between z = −2.49 and z = −1.85 is

Answer 1

The area to the left of z = −1.35 is

The area to the left of z = 0.46 is

The area to the right of z = 1.41 is

The area to the right of z = −1.12 is

The area between z = 0 and z = 3.00 is

P(0<z<3) = P ( Z<3 )−P (Z<0 )= 0.9987-0.5 = 0.4897

The area between z = 0 and z = −1.81 is

P (−1.81<Z<0 )=P ( Z<0 )−P (Z<−1.81 ) =0.5- 0.0351 = 0.4649

The area between z = −2.12 and z = 1.32 is

P (−2.21<Z<1.32 )=P ( Z<1.32 )−P (Z<−2.21 ) = 0.9066 - 0.0136 = 0.893

The area between z = 0.26 and z = 1.84 is

The area between z = −2.49 and z = −1.85 is