In: Advanced Math
Is there a difference between the means of occupancy rates in May and August? Answer your question by calculating an approximate and appropriate symmetric 95% confidence interval using a Z statistic. Explain your findings
| OR_MAY | OR_AUG |
| 60 | 97 |
| 86 | 99 |
| 93 | 99 |
| 89 | 96 |
| 74 | 90 |
| 81 | 84 |
| 83 | 99 |
| 71 | 99 |
| 90 | 98 |
| 83 | 97 |
| 77 | 99 |
| 82 | 97 |
| 90 | 98 |
| 81 | 98 |
| 20 | 90 |
| 87 | 95 |
| 48 | 94 |
| 60 | 96 |
| 45 | 98 |
| 80 | 95 |
| 65 | 91 |
| 60 | 95 |
| 75 | 90 |
| 15 | 70 |
| 16 | 66 |
| 97 | 100 |
| 74 | 94 |
| 62 | 97 |
| 40 | 85 |
| 82 | 97 |
| 24 | 76 |
| 49 | 98 |
| 16 | 93 |
| 60 | 86 |
| 42 | 73 |
| 68 | 87 |
| 55 | 86 |
| 75 | 93 |
| 35 | 95 |
| 0 | 95 |
| 40 | 80 |
| 40 | 40 |
| 10 | 80 |
| 83 | 90 |
| 50 | 100 |
| 77 | 98 |
| 81 | 99 |
| 37 | 96 |
| 27 | 90 |
| 49 | 96 |
| 53 | 98 |
| 60 | 97 |
| 80 | 100 |
| 58 | 95 |
| 64 | 93 |
| 65 | 100 |
| 68 | 98 |
| 75 | 100 |
| 55 | 84 |
| 60 | 95 |
| 56 | 96 |
| 10 | 100 |
| 85 | 95 |
| 4 | 77 |
| 24 | 92 |
| 85 | 98 |
| 75 | 92 |
| 44 | 84 |
| 45 | 95 |
| 0 | 70 |
| 34 | 92 |
| 35 | 95 |
| 70 | 98 |
| 65 | 99 |
| 15 | 90 |
| 40 | 100 |
| 10 | 90 |
| 10 | 90 |
| 35 | 70 |
| 50 | 100 |
| 2 | 95 |
| 0 | 80 |
| 3 | 90 |
| 30 | 90 |
| 15 | 80 |
| 83 | 95 |
| 91 | 99 |
| 85 | 100 |
| 80 | 90 |
| 50 | 100 |
| 79 | 94 |
| 92 | 98 |
| 87 | 99 |
| 84 | 97 |
| 65 | 98 |
| 86 | 94 |
| 62 | 92 |
| 70 | 95 |
| 87 | 97 |
| 87 | 99 |
| 50 | 97 |
| 61 | 97 |
| 59 | 99 |
| 77 | 100 |
| 46 | 95 |
| 81 | 94 |
| 48 | 98 |
| 15 | 98 |
| 80 | 100 |
| 52 | 99 |
| 90 | 97 |
| 90 | 99 |
| 75 | 90 |
| 20 | 100 |
| 10 | 90 |
| 30 | 100 |
| 53 | 99 |
| 52 | 99 |
| 90 | 97 |
| 53 | 92 |
| 48 | 98 |
| 84 | 96 |
| 90 | 97 |
| 35 | 98 |
| 25 | 95 |
| 35 | 100 |
| 10 | 95 |
| 10 | 90 |
| 60 | 100 |
| 70 | 92 |
| 3 | 78 |
| 10 | 90 |
| 10 | 90 |
| 75 | 100 |
| 10 | 70 |
Since , the formula to find Confidence Interval of a sample is given by -

where ,
for 95% confidence interval .
is the sample mean and
is the standard deviation of the given sample .
So let us first calculate standard deviation of the given sample , which is given by -

We have for data of month May -
Mean ,
= 54.05 . Therefore we have -
|
OR_MAY xi |
OR_AUG yi |
![]() |
| 60 | 97 | 35.4 |
| 86 | 99 | 1020.8 |
| 93 | 99 | 1517.1 |
| 89 | 96 | 1221.5 |
| 74 | 90 | 398 |
| 81 | 84 | 726.3 |
| 83 | 99 | 838.1 |
| 71 | 99 | 287.3 |
| 90 | 98 | 1292.4 |
| 83 | 97 | 838.1 |
| 77 | 99 | 526.7 |
| 82 | 97 | 781.2 |
| 90 | 98 | 1292.4 |
| 81 | 98 | 726.3 |
| 20 | 90 | 1159.4 |
| 87 | 95 | 1085.7 |
| 48 | 94 | 36.6 |
| 60 | 96 | 35.4 |
| 45 | 98 | 81.9 |
| 80 | 95 | 673.4 |
| 65 | 91 | 119.9 |
| 60 | 95 | 35.4 |
| 75 | 90 | 438.9 |
| 15 | 70 | 1524.9 |
| 16 | 66 | 1447.8 |
| 97 | 100 | 1844.7 |
| 74 | 94 | 398 |
| 62 | 97 | 63.2 |
| 40 | 85 | 197.4 |
| 82 | 97 | 781.2 |
| 24 | 76 | 903 |
| 49 | 98 | 25.5 |
| 16 | 93 | 1447.8 |
| 60 | 86 | 35.4 |
| 42 | 73 | 145.2 |
| 68 | 87 | 194.6 |
| 55 | 86 | 0.9 |
| 75 | 93 | 438.9 |
| 35 | 95 | 362.9 |
| 0 | 95 | 2921.4 |
| 40 | 80 | 197.4 |
| 40 | 40 | 197.4 |
| 10 | 80 | 1940.4 |
| 83 | 90 | 838.1 |
| 50 | 100 | 16.4 |
| 77 | 98 | 526.7 |
| 81 | 99 | 726.3 |
| 37 | 96 | 290.7 |
| 27 | 90 | 731.7 |
| 49 | 96 | 25.5 |
| 53 | 98 | 1.1 |
| 60 | 97 | 35.4 |
| 80 | 100 | 673.4 |
| 58 | 95 | 15.6 |
| 64 | 93 | 99 |
| 65 | 100 | 119.9 |
| 68 | 98 | 194.6 |
| 75 | 100 | 438.9 |
| 55 | 84 | 0.9 |
| 60 | 95 | 35.4 |
| 56 | 96 | 3.8 |
| 10 | 100 | 1940.4 |
| 85 | 95 | 957.9 |
| 4 | 77 | 2505 |
| 24 | 92 | 903 |
| 85 | 98 | 957.9 |
| 75 | 92 | 438.9 |
| 44 | 84 | 101 |
| 45 | 95 | 81.9 |
| 0 | 70 | 2921.4 |
| 34 | 92 | 402 |
| 35 | 95 | 362.9 |
| 70 | 98 | 254.4 |
| 65 | 99 | 119.9 |
| 15 | 90 | 1524.9 |
| 40 | 100 | 197.4 |
| 10 | 90 | 1940.4 |
| 10 | 90 | 1940.4 |
| 35 | 70 | 362.9 |
| 50 | 100 | 16.4 |
| 2 | 95 | 2709.2 |
| 0 | 80 | 2921.4 |
| 3 | 90 | 2606.1 |
| 30 | 90 | 578.4 |
| 15 | 80 | 1524.9 |
| 83 | 95 | 838.1 |
| 91 | 99 | 1365.3 |
| 85 | 100 | 957.9 |
| 80 | 90 | 673.4 |
| 50 | 100 | 16.4 |
| 79 | 94 | 622.5 |
| 92 | 98 | 1440.2 |
| 87 | 99 | 1085.7 |
| 84 | 97 | 897 |
| 65 | 98 | 19.9 |
| 86 | 94 | 1020.8 |
| 62 | 92 | 63.2 |
| 70 | 95 | 254.4 |
| 87 | 97 | 1085.7 |
| 87 | 99 | 1085.7 |
| 50 | 97 | 16.4 |
| 61 | 97 | 48.3 |
| 59 | 99 | 24.5 |
| 77 | 100 | 526.7 |
| 46 | 95 | 64.8 |
| 81 | 94 | 726.3 |
| 48 | 98 | 36.6 |
| 15 | 98 | 1524.9 |
| 80 | 100 | 673.4 |
| 52 | 99 | 4.2 |
| 90 | 97 | 1292.4 |
| 90 | 99 | 1292.4 |
| 75 | 90 | 438.9 |
| 20 | 100 | 1159.4 |
| 10 | 90 | 1940.4 |
| 30 | 100 | 578.4 |
| 53 | 99 | 1.1 |
| 52 | 99 | 4.2 |
| 90 | 97 | 1292.4 |
| 53 | 92 | 1.1 |
| 48 | 98 | 36.6 |
| 84 | 96 | 897 |
| 90 | 97 | 1292.4 |
| 35 | 98 | 362.9 |
| 25 | 95 | 843.9 |
| 35 | 100 | 362.9 |
| 10 | 95 | 1940.4 |
| 10 | 90 | 1940.4 |
| 60 | 100 | 35.4 |
| 70 | 92 | 254.4 |
| 3 | 78 | 2606.1 |
| 10 | 90 | 1940.4 |
| 10 | 90 | 1940.4 |
| 75 | 100 | 438.9 |
| 10 | 70 | 1940.4 |
Thus ,
Standard deviation = 27.6779
Mean
= 54.05
Therefore, from (1);





Similarly , standard deviation of data of month august = 858.819595
Mean ,
= 167.87
Therefore ,
From (1)





Thus, from the two confidence intervals , we can say that the occupancy rate in may lies between ( 49.35 , 58.75 ) and that in june lies between ( 21.91 , 313.83 )
Thus , there is a difference between the two occupancy rates of two months . The OR in June has more wide range than that in May .