In: Statistics and Probability
1. In an area of the Midwest, records were kept on the
relationship between the rainfall (in inches)
and the yield of wheat (bushels per acre).
|
Rain (inches) |
10.5 |
8.8 |
13.4 |
12.5 |
18.8 |
10.3 |
7.0 |
15.6 |
16.0 |
|
Yield (bushels/acre) |
50.5 |
46.2 |
58.8 |
59.0 |
82.4 |
49.2 |
31.9 |
76.0 |
78.8 |
Find the correlation coefficient for the given data.
a. 4.267
b. 0.9808
c. 0.9620
d. 3.158
2.
A study was conducted to compare the average time spent in the
lab each week versus course grade for computer programming
students. The results are recorded in the table below:
Hours spent in lab .. Grade (percent)
10 96
11 51
16 62
9 58
7 89
15 81
16 46
10 51
Find the value of the linear correlation coefficient r.
a. 0.462
b. -0.335
c. 0.017
d. -0.284
3. Applicants for a particular job, which involves extensive
travel in Spanish speaking countries,
must take a proficiency test in Spanish. The sample data below were
obtained in a study of the
relationship between the numbers of years applicants have studied
Spanish and their score on the test.
|
Number of years (x) |
Score (y) |
|
3 |
57 |
|
4 |
78 |
|
4 |
72 |
|
2 |
58 |
|
5 |
89 |
|
3 |
63 |
|
4 |
73 |
|
5 |
84 |
|
3 |
75 |
|
2 |
48 |
Determine whether the data provide sufficient evidence to conclude
that number of years of study
and test score are positively linearly correlated. Test at the 5%
significance level.
a. Test statistic: t = 0.83654
Do not reject H0. At the 5% significance level, the data
do not provide sufficient evidence to conclude that number of years
of study and test score are positively linearly correlated.
b.Test statistic: t = 0.91463
Do not reject H0. At the 5% significance level, the data
do not provide sufficient evidence to conclude that number of years
of study and test score are positively linearly correlated.
c.Test statistic: t = 5.3294
Reject H0. At the 5% significance level, the data
provide sufficient evidence to conclude that number of years of
study and test score are positively linearly correlated.
d. Test statistic: t = 6.2525
Reject H0. At the 5% significance level, the data
provide sufficient evidence to conclude that number of years of
study and test score are positively linearly correlated.
4.Given the linear correlation coefficient r and the
sample size n, determine the critical
values of r and use your finding to state whether or not the given
r represents a
significant linear correlation. Use a significance
level of 0.05.
r = 0.539, n = 25
a. Critical values: r = 0.396, no significant linear correlation
b. Critical values: r = 0.487, no significant linear correlation
c. Critical values: r = 0.487, significant linear correlation
d. Critical values: r = 0.396, significant linear correlation
1. Correlation coefficient
The formula of correlation coefficient

n = number of pairs = 9
X: Rain and Y: Yield


Correlation coefficient (r) = 0.9808
Option b is correct.
2.
The formula of correlation coefficient

n = number of pairs = 8
X: Hours spent and Y: Percent


Correlation coefficient (r) = -0.335
Option b is correct.
3.
The formula of correlation coefficient

n = number of pairs = 10
X: Number of years and Y: Score


The null and alternative hypothesis
H0: There is no linear correlation between the number of years of study and test scores.
H1: There is positive linear correlation between the number of years of study and test scores.
The test statistics is

t critical value using the n - 2 that is 8 degrees of freedom with the area in one tailed as alpha 0.05 is 1.86
If critical value > test statistics then fail to reject the H0 otherwise reject the H0
Critical value 1.86 is less than test statistics that is 6.2525 so reject the null hypothesis.
Option d is correct.
d: Test statistic: t = 6.2525
Reject H0. At the 5% significance level, the data
provide sufficient evidence to conclude that number of years of
study and test score are positively linearly correlated.
4.
The null and alternative hypothesis are,
H0: There is no significant linear correlation.
H1: There is significant linear correlation.
n = 25 , alpha = 0.05
Degrees of freedom = n - 2 = 23, the test is two-tailed test.
The critical value using the critical value table for degrees of freedom 23 and alpha 0.05 in two tailed is 0.396
Critical value = 0.396, r = 0.539
Critical value is not more than r so reject the null hypothesis.
Reject the null means there is significant linear correlation.
Option d is correct.
d. Critical values: r = 0.396, significant linear correlation.