Question
In: Statistics and Probability
in a random sample of 30 arthrose Copic surgeries, 4% were unsuccessful. Find a 95% confidence...
in a random sample of 30 arthrose Copic surgeries, 4% were unsuccessful. Find a 95% confidence interval for the proportion of arthroscopic surgery the population that were unsuccessful
Solutions
orchestra answered 2 years agoRelated Solutions
In a random sample of 144 observations, = .7. The 95% confidence interval for p is
In a random sample of 144 observations, = .7. The 95% confidence
interval for p is
A random sample of 121 observations produced a sample proportion of 0.4. An approximate 95% confidence...
A random sample of 121 observations produced a sample proportion
of 0.4. An approximate 95% confidence interval for the population
proportion p is between
A random sample of 140 observations results in 119 successes. a. Construct the a 95% confidence...
A random sample of 140 observations results in 119
successes.
a. Construct the a 95% confidence interval for the
population proportion of successes. (Round intermediate
calculations to at least 4 decimal places. Round "z" value
and final answers to 3 decimal places.)
b. Construct the a 95% confidence interval for
the population proportion of failures. (Round intermediate
calculations to at least 4 decimal places. Round "z" value
and final answers to 3 decimal places.)
Construct a 95% confidence interval for the population standard deviation of a random sample of 15...
Construct a 95% confidence interval for the population standard
deviation of a random sample of 15 crates which have a mean weight
of 165.2 points and a standard deviation of 12.9 pounds. Assume the
population is normallyn distributed.
A. 9.9, 18.8
B. 9.4, 20.3
Please show work.
q2.A random sample of 121 observations produced a sample proportion of 0.35. An approximate 95% confidence...
q2.A random sample of 121 observations produced a sample
proportion of 0.35. An approximate 95% confidence interval for the
population proportion p is between
a) 0.265 and 0.421 b) 0.307 and 0.393 c) 0.265 and 0.435 d)
0.245 and 0.455 e) 0.279 and 0.421
1 Joe computed a 95% confidence interval for µ from a specific random sample. His confidence...
1 Joe computed a 95% confidence interval for µ from a specific
random sample. His confidence interval was 10.1<µ<12.2. He
claims that the probability that µ is in this interval
0.95. What is wrong with his claim? Explain.
2. Consider a test for µ. If the P-value is such that you can
reject H0 for α=0.01, can you always reject H0 for α =0.05?
Explain.
PLZ PLZ help me with 1 and 2 and plz write in your own words...
Find the requested confidence interval. A random sample of 30 long distance runners aged 20-25 was...
Find the requested confidence interval. A random sample of 30
long distance runners aged 20-25 was selected from a running club.
The mean of resting heart rates (in beats per minute) of the
runners taken in this sample is 68.07 Estimate the mean resting
heart rate for the population of long distance runners aged 20-25.
Assuming ? = 8.03, give the 95.44% confidence interval for the
population mean.
Assume that a sample is used to estimate a population proportion p. Find the 95% confidence...
Assume that a sample is used to estimate a population proportion
p. Find the 95% confidence interval for a sample of size
252 with 79% successes. Enter your answer as a tri-linear
inequality using decimals (not percents) accurate to three decimal
places.
< p <
Assume that a sample is used to estimate a population proportion p. Find the 95% confidence...
Assume that a sample is used to estimate a population proportion
p. Find the 95% confidence interval for a sample of size 287 with
207 successes. Enter your answer as a tri-linear inequality using
decimals (not percents) accurate to three decimal places.
< p
Assume that a sample is used to estimate a population mean μ. Find the 95% confidence...
Assume that a sample is used to estimate a population mean μ.
Find the 95% confidence interval for a sample of size 1037 with a
mean of 38.4 and a standard deviation of 19.2. Enter your answer as
a tri-linear inequality accurate to 3 decimal places.
_______< μ < _______
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