In: Statistics and Probability
q2.A random sample of 121 observations produced a sample proportion of 0.35. An approximate 95% confidence interval for the population proportion p is between
a) 0.265 and 0.421 b) 0.307 and 0.393 c) 0.265 and 0.435 d) 0.245 and 0.455 e) 0.279 and 0.421
Solution :
Given that,
n = 121
Point estimate = sample proportion = =0.35
1 - = 1-0.35 =0.65
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96 ( Using z table )
Margin of error = E = Z/2 * ((( * (1 - )) / n)
= 1.96 (((0.35*0.65) / 121)
E = 0.085
A 95% confidence interval for population proportion p is ,
- E < p < + E
0.35-0.085 < p < 0.35+0.085
0.265 and 0.435