Question

In: Statistics and Probability

In an experiment, participants were shown three of the famous Rorschach “inkblot” images, each accompanied by...

In an experiment, participants were shown three of the famous Rorschach “inkblot” images, each accompanied by an actual response from a patient undergoing psychiatric evaluation. They were asked: “Based on this response to the inkblot, how unstable do you think the patient is, on a scale from 1 (very stable) to 10 (very unstable)?"

They were divided into two experimental groups: Group 1 had patients with common names (Sara, Mary, John) and Group 2 had patients with uncommon names (Desdemona, Edmund, Roderick).

The hypothesis was that there is a bias against patients with uncommon names, such that their responses will seem more unstable. Use these results to answer the questions

Group 1 (common): M1 = 5.04, n1 = 32, s21 = 2.68

Group 2 (uncommon): M2 = 5.30, n2 = 32, s22 = 2.13

A. What is the pooled variance, s2p?

B. What is the estimated standard error, s(M1–M2) ?

C.

What is the t-stat (Remember: this is an independent samples t-test)?

D. What is the r2 effect size measure?

E. Write a proper sentence reporting the results of the t-test and the effect size measure. You may chose your own alpha-criterion and whether to do one- or two-tailed, but be sure to include that information in your sentence.

Solutions

Expert Solution

NULL HYPOTHESIS H0:

ALTERNATIVE HYPOTHESIS Ha:

Group 1 (common): M1 = 5.04, n1 = 32, s21 = 2.68

Group 2 (uncommon): M2 = 5.30, n2 = 32, s22 = 2.13

A] POOLED VARIANCE= s1^2(n1-1)+s2^(n2-1)/n1+n2-2

= 2.404

B] Standard error = 0.3876

C] test statistic t= difference of means/Standard error of mean

= -0.26/0.3876

= -0.6707

The p-value is .252673.The result is not significant because p > .05.

D] r^2= t^2/t^2+df

= (-0.671)^2/(-0.671)^2+62

= 0.00721 VERY SMALL EFFECT SIZE

E] CONCLUSION: We donot have suuficient evidence to conclude that  there is a bias against patients with uncommon names at 0.05 level of significance .


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