Question

In: Economics

Suppose a polluter initially faces marginal abatement curve MAC1 = 320-10E1 , but it has the...

  1. Suppose a polluter initially faces marginal abatement curve MAC1 = 320-10E1 , but it has the possibility of investing in R&D and thereby lowering its marginal abatement cost curve to MAC2 = 160 – 5E2. Compute the cost savings to the polluter if it adopts the new technology (MAC2) after the introduction of an emissions tax of $100 per tonne. Compute the cost savings under a standard that is set at 20 tonnes. Explain why the tax provides a larger incentive to innovate than does the standard. (10 points)

Solutions

Expert Solution

Answer :

So, here “MAC1=320-10*E1”, => at the optimum without any tax the firm will choose “E1” such that “MAC1=0”, => E1= 320/10=32”. Now, after the introduction of tax of “100 per ton” the optimum “E1” is given by, “MAC1=100”, => E1 = (320-100)/10 = 22=E1”. So, here the total cost is given by.

=> Total Cost = total abatement cost + total tax

= 0.5*100*(32-22) + 100*22 = 500 + 2200.

=> Total Cost = 2,700.

For new technology “MAC2=160-5*E2”, => at the optimum without any tax the firm will choose “E2” such that “MAC2=0”, => E2= 160/5=32”. Now, after the introduction of tax of “100 per ton” the optimum “E2” is given by, “MAC2=100”, => E2 = (160-100)/5 = 12=E2”. So, here the total cost is given by.

=> Total Cost = total abatement cost + total tax

= 0.5*100*(32-12) + 100*12 = 1000 + 1200.

=> Total Cost = 2,200.

So, here the total cost savings is given by “2,700-2,200 = 500”.

Now, let’s assume that if a standard is set at “20 tones”, => at “E1=20”, => “MAC1=320-10*E1 = 120”, => her the total cost is given by, “0.5*(32-20)*120 = 720. Now, under the new technology at the emission level “E2=20” the corresponding “MAC” is given by “MAC2=60”, => here the total cost is given by “0.5*60*(32-20) = 360”. So, here the total cost savings is given by “720-360 = 360”.

So, here we can see that the cost savings is more under “tax” compare to under the “emission standard”. Now, under the 2nd case the level of standard is fixed at “E=20” but at this level of standard “MAC2 > T=100”, => it is optimum to reduce the level of emission, but here we are not changing it, => optimum level of emission is not chosen, => cost savings is less under emission standard


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