Question

Write a program in assembly language that outputs the leap years between a beginning and an ending year.

1. Initialize $a0 and $a1 with the beginning and ending years.
2. Print out the leap years between 1970 and 2030.

OUTPUT:
From 1970 to 2030:
1972
…
2028

Answer 1

.data
newline: .asciiz "\n"
.text
.globl main
main:
   li $a0, 1970
   li $a1, 2030
  
find:       #finding first leap year from starting $a0
   move $t1, $a0
   li $t2, 4
   div $t1, $t2
   mfhi $t2
   beq $t2, 0, print
   addi $a0, $a0, 1
   j find

print:       # print all the leap by incrementing by 4 to the fisrt leap year
   slt $t3, $a1, $t1
   beq $t3, 1, end
   li $v0, 1
   move $a0, $t1
   syscall
   li $v0, 4
   la $a0, newline
   syscall
   addi $t1, $t1, 4
   j print

end:
   li $v0, 10
   syscall
   

#Output