Question

In: Physics

I've already worked out the vertical and horizontal components so far for this question. Vertical component=16.34...

I've already worked out the vertical and horizontal components so far for this question. Vertical component=16.34 and horizontal component=25.16 but I got no idea what to do from here. A polo ball is hit from the ground at an angle of 33 degrees upwards from the horizontal. If it has a release velocity of 30 m/s and lands on the ground.

Based on the initial release parameters, what will the polo ball's vertical and horizontal velocity components be at the instant before it lands on the ground?

a. vertical?

b.horizontal?

Expert Solution

Initial speed of the ball is v_o=30m/s

Initial horizontal velocity of the ball is

Initial vertical velocity of the ball is

(a)

The vertical acceleration of the ball is

The height of the ball at the ground is y=0. The vertical acceleration of the ball is constant, the vertical motion of the ball is governed by the kinematics equation for uniformly accelerated motion. The vertical position of the ball as a function is

The height of the ball is zero at time t=0 (when it was released from ground). It lands on the ground at time

Vertical velocity of the ball just before it lands is

The vertical velocity is negative representing that the ball is moving vertically downward just before it lands.

(b)

There is no force on the ball in the horizontal direction, the horizontal acceleration of the ball is zero. The horizontal velocity of the ball does not change with time. The horizontal velocity of the ball just before it lands on the ground is

genius_generous answered 2 years ago

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