In: Statistics and Probability
The following results are from data concerning the amount
withdrawn from an ATM machine based on the amount of time spent at
the ATM machine (SECONDS) and the gender, FEMALE (dummy variable =
1 for females and = 0 for males) and an interaction term,
SECONDS*FEMALE
SUMMARY OUTPUT |
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Regression Statistics |
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Multiple R |
0.503 |
|||||
R Square |
||||||
Adjusted R Square |
||||||
Standard Error |
||||||
Observations |
50 |
|||||
ANOVA |
||||||
df |
SS |
MS |
F |
Significance F |
||
Regression |
2728.7 |
5.19 |
0.004 |
|||
Residual |
24161.8 |
525.3 |
||||
Total |
32348 |
|||||
Coefficients |
Standard Error |
t Stat |
P-value |
Lower 95% |
Upper 95% |
|
Intercept |
133.5 |
23.51 |
5.89 |
0 |
91.03 |
185.67 |
Seconds |
-2 |
0.679 |
0.002 |
-3.401 |
-0.839 |
|
Female |
-78.6 |
30.3 |
-2.26 |
-137.33 |
-8.07 |
|
Seconds*Female |
2.3 |
0.85 |
2.8 |
0.007 |
0.67 |
Based on the regression results, when testing to see if the
coefficient on FEMALE is different than -100, what
is the critical value (using the 5% level of significance)? (please
express your answer using 2 decimal places)
Let be the coefficient on Female. Then the hypotheses are
Null Hypotheis H0: = -100
Alternative Hypothesis H1: -100
Test statistic, t = (Observed Coeff - Hypothesized Coeff) / Standard error
= (-78.6 - (-100)) / 30.3
= 0.7063
Degree of freedom = Number of Observations - Number of predictors - 1
= 50 - 3 - 1
= 46
For two tail test, Critical value of t at 5% level of significance and df = 46 is 2.01
We reject H0 when observed test statistic, t < -2.01 or t > 2.01
Since the observed test statistic (0.7063) does not lie in the rejection region, we fail to reject H0 and conclude that there is no significant evidence that -100. That is, there is no significant evidence that the coefficient on FEMALE is different than -100