Question

In: Statistics and Probability

The following results are from data concerning the amount withdrawn from an ATM machine based on...

The following results are from data concerning the amount withdrawn from an ATM machine based on the amount of time spent at the ATM machine (SECONDS) and the gender, FEMALE (dummy variable = 1 for females and = 0 for males) and an interaction term, SECONDS*FEMALE

  

SUMMARY OUTPUT

Regression Statistics

Multiple R

0.503

R Square

Adjusted R Square

Standard Error

Observations

50

ANOVA

df

SS

MS

F

Significance F

Regression

2728.7

5.19

0.004

Residual

24161.8

525.3

Total

32348

Coefficients

Standard Error

t Stat

P-value

Lower 95%

Upper 95%

Intercept

130.9

23.51

5.89

0

91.03

185.67

Seconds

-2.07

0.636

0.002

-3.401

-0.839

Female

-75.7

30.8

-2.26

-137.33

-8.07

Seconds*Female

2.4

0.88

2.8

0.007

0.67


  
Based on the regression results, if a male and female each spend the same amount of time at the ATM matchine (say 38 seconds), how much more (or less) will a male withdraw? (if a male withdraws more then your answer should be a positive number and if a male withdraws less then your answer should be a negative number? (please express your answer using 1 decimal places)

Solutions

Expert Solution

Answer:

giventhat

Multiple R=R=0.503

R-Square=R2=R*R=0.503*0.503=0.253

Adjusted R square=1-(1-R2)*(N-1)/(N-p-1)=1-(1-0.253)*49/(50-3-1)=0.2043

Residual df=SS(residual)/MS(residual)=24161.8/525.3=45.99 ( next integer is 46)

Total df=N-1=50-1=49

Regression df=Total df - Residual df=49-46=3

confidence interval is equidistant from respective coefficient in this case due to symmetric nature of t-distribution

so Upper 95%=2.4+(2.4-0.76)=4.04

please check your question it is not matching t-stat =coefficient/SE(coefficient)

t-stat=coefficint/SE(coefficient)

P-value is calcuated using ms-excel command=tdist(t-stat, df,two tailed)

for intercept P-value=tdist(5.89, 46,2)=0.000


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