In: Statistics and Probability
Your professor wants to know if all tests are created equal.
What is the F-Stat? Use Excel.
| EXAM1 | EXAM2 | EXAM3 | FINAL |
| 73 | 80 | 75 | 65.86667 |
| 93 | 88 | 93 | 80.16667 |
| 89 | 91 | 90 | 78 |
| 96 | 98 | 100 | 84.93333 |
| 73 | 66 | 70 | 61.53333 |
| 53 | 46 | 55 | 43.76667 |
| 69 | 74 | 77 | 64.56667 |
| 47 | 56 | 60 | 49.83333 |
| 87 | 79 | 90 | 75.83333 |
| 79 | 70 | 88 | 71.06667 |
| 69 | 70 | 73 | 61.1 |
| 70 | 65 | 74 | 61.1 |
| 93 | 95 | 91 | 79.73333 |
| 79 | 80 | 73 | 65.86667 |
| 70 | 73 | 78 | 64.13333 |
| 93 | 89 | 96 | 83.2 |
| 78 | 75 | 68 | 63.7 |
| 81 | 90 | 93 | 79.3 |
| 88 | 92 | 86 | 76.7 |
| 78 | 83 | 77 | 68.9 |
| 82 | 86 | 90 | 76.7 |
| 86 | 82 | 89 | 75.83333 |
| 78 | 83 | 85 | 75.83333 |
| 76 | 83 | 71 | 64.56667 |
| 96 | 93 | 95 | 83.2 |
Run Anova single factor analysis to find whether all means are equal or not.
1. Bring data in to excel sheet.
2. Go to data tab -- > choose data analysis --> choose Anova single factor

Output:

F-stat: 4.52
P-value 0.005
so, P-value is less tha the significance level 0.05
If the p-value is less than 0.05, we reject the null hypothesis that there's no difference between the means and conclude that a significant difference does exist