In: Chemistry
in CaCl2 solution :
CaCl2 concentration = 0.55 M
Cl concentration = 2 x 0.55 = 1.1 M
PbCl2 -------------------> Pb+2 + 2 Cl-
S 2S in water
S 2S + 1.1 (from CaCl2)
S 1.1
Ksp = [Pb+2][Cl-]^2
1.2 x 10^-5 = S x 1.1^2
S = 9.92x 10^-6 M ----------------------------------(1)
in HCl solution:
HCl concentration = 0.65 M
Cl concentration = 0.65 M
PbCl2 -------------------> Pb+2 + 2 Cl-
S 2S in water
S 2S + 0.65 (from CaCl2)
S 0.65
Ksp = [Pb+2][Cl-]^2
1.2 x 10^-5 = S x 0.65^2
S = 2.84 x 10^-5 M -----------------------------(2)
lead chloride solubility is more in HCl